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DedPeter [7]
3 years ago
5

585=5x^3 solve for x

Mathematics
1 answer:
Nikolay [14]3 years ago
5 0
<span>585=<span>5<span>x3</span></span></span>Step 1: Subtract 5x^3 from both sides.<span><span>585−<span>5<span>x3</span></span></span>=<span><span>5<span>x3</span></span>−<span>5<span>x3</span></span></span></span><span><span><span>−<span>5<span>x3</span></span></span>+585</span>=0</span>Step 2: Subtract 585 from both sides.<span><span><span><span>−<span>5<span>x3</span></span></span>+585</span>−585</span>=<span>0−585</span></span><span><span>−<span>5<span>x3</span></span></span>=<span>−585</span></span>Step 3: Divide both sides by -5.<span><span><span>−<span>5<span>x3</span></span></span><span>−5</span></span>=<span><span>−585</span><span>−5</span></span></span><span><span>x3</span>=117</span>Step 4: Take cube root.<span>x=<span><span>(117)</span><span>(<span>13</span>)</span></span></span><span>x=4.890973</span>Answer:<span>x=4.890973</span> glad to help!

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Subtract (In picture)
Sonbull [250]

--First we have to simplfy

\frac{2x-8}{x^2-x-12} -\frac{x-3}{x(x+1)}

\frac{2(x-4)}{(x-4)(x+3)} - \frac{x-3}{x(x+1)}

--Cancel common factors

\frac{2}{(x+3)} -\frac{x-3}{x(x+1)}

--Here remember never cancel factors in a subtraction or addition problem

--Now Multiply each side until both denominators are equal to each other

\frac{2[x(x+1)]}{x(x+3)(x+1)} -\frac{(x-3)(x+3)}{x(x+3)(x+1)}

--Simplify

\frac{2x^2+2x}{x(x+1)(x+3)} - \frac{x^2-9}{x(x+1)(x+3)}

--Now that the denominators are the same: subtract!

\frac{2x^2+2x-(x^2-9)}{x(x+1)(x+3)}

\frac{2x^2-x^2+2x+9}{x(x+1)(x+3)}

--And LAST STEP! ......Simplify More.... To get your answer

\frac{x^2+2x+9}{x(x+1)(x+3)}


6 0
3 years ago
Let's find +1418.
zysi [14]

Answer:

u just explained ur answer

Step-by-step explanation:

7 0
2 years ago
What is the slope of the function, represented by the table of values below ?
Komok [63]
For a given function, slope is defined as the change in outputs, or y-values divided by the change in inputs, or x-values. In essence the slope asks "For a given change in x, how much does y change?" or even more simply: "How steep is the graph of this function?". This can be represented mathematically by the formula:
m=\frac{rise}{run}=\frac{\Delta y}{\Delta x}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Since we have a table of x,y pairs it's the last form of that equation that will be the most useful to us. To compute the slope we can use any two pairs, say the first two, and plug them into our formula:
m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{4-10}{0-(-2)}=\frac{-6}{2}=-3

We can check this answer by using a different pair, say the last two:
m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{(-23)-(-14)}{9-6}=\frac{-9}{3}=-3.

As a common sense check: Our y-values get smaller as our x-values get bigger so a negative slope makes sense. 

m=-3
5 0
3 years ago
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answer is first expresion
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