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Gelneren [198K]
3 years ago
15

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Evgen [1.6K]3 years ago
7 0

Answer:

  plot the points (0, 2) and (π, 4)

Step-by-step explanation:

To use your sine plotting tool, you need two points on the graph. The midline point is given for you. It is the y-intercept, (0, 2).

The maximum amplitude point is 1/4 of a period from this midline point. The frequency is 1/(4π), and the period is the inverse of frequency:

  T = 1/f = 4π

So, 1/4 of a period is ...

  T/4 = (4π)/4 = π

The peak value of the function is the amplitude added to the midline, so is 2+2 = 4.

The second point you need to plot is the peak value, (π, 4).

Your points are (0, 2) and (π, 4).

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HELP I NEED HELP ASAP
Kaylis [27]

Answer:

so how many units are they away from each other

Step-by-step explanation:1,

1.1-2.0  how many units are they away from each other

u could drag the number from the top to the chart below

good luck!

6 0
3 years ago
How do you find the surface area if your radius is 5 and your length is 10
ser-zykov [4K]
Surface Area of a Cone = (pi)*(radius)*(radius) + (pi)*(radius)*(length)

radius = 5
length = 10

SA = 25pi + 50pi = 75pi or about 235.619
6 0
3 years ago
John has a job parking cars. He earns a fixed weekly salary of $300 plus a fee of $5 for each car he parks. At what point does J
horrorfan [7]
Let us assume the number of cars parked after which John will start earning more than his fixed weekly salary = x
The fixed weekly salary of John = $300
The fee that John gets for parking each car = $5
Then we can get the equation as
5x = 300
x = 300/5
   = 60
So from the above deduction we can see that John will earn the equal amount of his weekly pay after he parks 60 cars. Then it becomes obvious that parking car number 61, John will start earning more than what he gets as his fixed weekly salary. I hope you have understood the described method.
4 0
3 years ago
Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
What is the difference between a right, acute, and obtuse triangle?
kakasveta [241]

A right triangle has one angle that's 90° and a corner that looks like an L. Obtuse triangles have one angle that's greater than 90°. In acute triangles, all the angles are less than 90°.

Step-by-step explanation:

7 0
3 years ago
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