i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X
Hope this helps...
Good luck on your assignment...
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!
1 answer:
Answer:
plot the points (0, 2) and (π, 4)
Step-by-step explanation:
To use your sine plotting tool, you need two points on the graph. The midline point is given for you. It is the y-intercept, (0, 2).
The maximum amplitude point is 1/4 of a period from this midline point. The frequency is 1/(4π), and the period is the inverse of frequency:
T = 1/f = 4π
So, 1/4 of a period is ...
T/4 = (4π)/4 = π
The peak value of the function is the amplitude added to the midline, so is 2+2 = 4.
The second point you need to plot is the peak value, (π, 4).
Your points are (0, 2) and (π, 4).
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