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Paha777 [63]
3 years ago
14

Based on each person's statements, identify which of the following you AGREE with, and then explain your reasoning.

Biology
1 answer:
Andreyy893 years ago
6 0

courtneys statement is right

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All of the following are common conflicts EXCEPT Select one: a. Character vs. self b. Character vs. character c. Character vs. n
DaniilM [7]
Character vs technology

The four types of conflicts are:
1. Character vs character
2. Character vs society
3. Character vs itself
4. Character vs nature
7 0
3 years ago
What is the basis of the metric system of measurement?
prisoha [69]

Base units for mass, length, time, and charge, and the number 10. All metric units, quantities, and operations are combinations of these.

Example: 1 micro-Newton (a tiny force) is 1 kilogram-meter per second squared times 10^-6.

5 0
3 years ago
In organisms with large genomes, inversions are more likely to be tolerated if the breakpoints occur in: reciprocal translocatio
andre [41]

Answer:

Non-coding DNA.

Explanation:

Inversion is a type of chromosomal abnormality in which the sequence of a segment of a chromosome is inverted or rotated at an angle of 180 degrees.  This type of abnormality can change the reading frame of the gene and can cause mutations.

But if the genome sequence is non-coding that is not involved in the formation of protein synthesis than even if the reading frame is inverted will not affect the phenotype of the cell. Also, the non-coding sequences are removed by the splicing mechanisms.

Thus, Non-coding DNA is correct.

4 0
3 years ago
A cell in the testes of a male bald eagle is getting ready to begin meiosis. The diploid number for this bird species is 66. How
Ostrovityanka [42]

Answer:

Replicated chromosomes at metaphase I = 66

Sister chromatids at metaphase I = 66 x 2 = 132

Sister chromatids at prophase II = 66

Chromosomes in each sperm cells = 33

Explanation:

Metaphase I of meiosis I would have 66 replicated chromosomes in the testicular cells of the bird. Each of the replicated chromosomes would have two sister chromatids. So, a total of 66 replicated chromosomes would have 66 x 2 = 132 sister chromatids.  

Due to segregation of homologous chromosomes towards opposite poles in anaphase I, each daughter cell formed by the end of meiosis I would have 33 replicated chromosomes. So, each of the daughter cells would have a total 33 x 2 = 66 sister chromatids at prophase II.  

Since meiosis II maintains the chromosome number, each sperm cell formed by the end of meiosis II would have 33 chromosomes.  

8 0
3 years ago
PLEASE HELP <br> here is my question
BaLLatris [955]
B
Now lol I have an A+ in that class
5 0
2 years ago
Read 2 more answers
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