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Sophie [7]
3 years ago
6

Simplify 9 to the second power over 9 to the seventh power.

Mathematics
1 answer:
Ugo [173]3 years ago
6 0
9^2  subtract the exponents. 9^-5 can't have that so flip the fraction.
----
9^7

1
---     is the answer
9^5
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the area of the first quadrant bounded by the y-axis, the line y=4-x, and the graph of y=x-cosx is approximately
zzz [600]
The curves y=4-x and y=x-\cos x intersect at approximately x\approx1.8582. The area is then

A\approx\displaystyle\int_0^{1.8582}((4-x)-(x-\cos x))\,\mathrm dx=\int_0^{1.8582}(4-2x+\cos x)\,\mathrm dx\approx4.9389
7 0
4 years ago
I kinda forgot my fractions. Anybody nice to help? 17/21 - 1/7. Answer in simplest form. Thanks!
jeka94

Answer:

2/3

Step-by-step explanation:

17/21-1/7

17/21-3/21

14/21=2/3

6 0
2 years ago
Ken has 4.66 pounds of walnuts, 2.1 pounds of cashews, and 8 pounds of peanuts. He mixes them together and divides them equally
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5 0
3 years ago
-4v³+11v²-6v how to factor
Nady [450]

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4 0
3 years ago
Q6 Q15.) Which of the following four statements establishes the​ identity?
erastova [34]
A is incorrect. The identity is for the Sin( A - B). It is not for the Cos(A - B)

B is closer, but NOT the answer. The sign in the middle is incorrect, for one thing. For another Cos(pi/2) = 0,, so the answer would be cos(theta) using this formula.

C The sign is correct in C. The problem is that it is the wrong formula for Cos(theta - pi/2). C should go 
Cos(theta - pi/2) = cos(theta) cos(pi/2) + sin(theta)*sin(pi/2)

D. Looks like it's the correct answer. See the comment for C: The identity for C is actually correct for D.
Cos(theta)cos(pi/2) = 0 because cos(pi/2) =0
Sin(theta)*sin(pi/2) = Sin(theta) because Sin(pi/2) = 1

Answer D <<<<<< answer.


8 0
4 years ago
Read 2 more answers
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