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iogann1982 [59]
3 years ago
15

Ken has 4.66 pounds of walnuts, 2.1 pounds of cashews, and 8 pounds of peanuts. He mixes them together and divides them equally

among 18 bags. How many pounds of nuts are in each bag?
Mathematics
1 answer:
Nat2105 [25]3 years ago
5 0
7.20 pounds in each... IM SRRY IF WRONG
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All you have to do is multiply 2.3 by 13 together to get 29.9. Then you would subtract that by the total volume which would get 107.64. That's the width.
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A vial contains 20mL of medicine.If each dose is 1/3 of the vial,how many mL is each dose.Express your answer as a decimal
Genrish500 [490]

Answer:

each dose = 6.7 mL ( to 1 decimal place)

Step-by-step explanation:

Total volume of vial = 20mL

each dose of vial = 1/3 of the total volume

let us express this fraction as a real number:

1/3 of 20 = 1/3 × 20

Since we are to express the answer as a decimal, let us convert the fraction to decimal:

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since we are dealing with drugs, it'll be appropraite to express the answer to 1 d.p

∴ each dose = 6.7 mL

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3 years ago
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Sergeeva-Olga [200]

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7 0
3 years ago
An elementary school is offering 2 language classes: one in Spanish (S) and one in French (F). Given that P(S) = 50%, P(F) = 40%
nikklg [1K]

Answer:

(a) Probability that a randomly selected student is taking Spanish given that he or she is taking French = 0.5 .

(b) Probability that a randomly selected student is not taking French given that he or she is not taking Spanish = 0.6 .

Step-by-step explanation:

We are given that an elementary school is offering 2 language classes ;

 <em>Spanish Language is denoted by S and French language is denoted by F.</em>

Also we are given, P(S) = 0.5 {Probability of students taking Spanish language}

P(F) = 0.4 {Probability of students taking French language}

P(S\bigcup F) = 0.7 {Probability of students taking Spanish or French Language}

<em>We know that,  </em>P(A\bigcup B)<em>  = </em>P(A) + P(B) -<em> </em>P(A\bigcap B)<em />

So, P(S\bigcap F) = P(S) + P(F) - P(S\bigcup F) = 0.5 + 0.4 - 0.7 = 0.2

P(S\bigcap F) means Probability of students taking  both Spanish and French Language.

Also, P(S)' = 1 - P(S) = 1 - 0.5 = 0.5

         P(F)' = 1 - P(F) = 1 - 0.4 = 0.6

        P(S'\bigcap F') = 1 -  P(S\bigcup F) = 1 - 0.7 = 0.3

(a) Probability that a randomly selected student is taking Spanish given that he or she is taking French is given by P(S/F);

  P(S/F) = \frac{P(S\bigcap F)}{P(F)} = \frac{0.2}{0.4} = 0.5

(b) Probability that a randomly selected student is not taking French given that he or she is not taking Spanish is given by P(F'/S');

   P(F'/S') = \frac{P(S'\bigcap F')}{P(S')} = \frac{1- P(S\bigcup F)}{1-P(S)} = \frac{0.3}{0.5} = 0.6 .

Note: 2. A pair of fair dice is rolled until a sum of either 5 or 7 appears  ; This question is incomplete please provide with complete detail.

7 0
4 years ago
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