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iogann1982 [59]
3 years ago
15

Ken has 4.66 pounds of walnuts, 2.1 pounds of cashews, and 8 pounds of peanuts. He mixes them together and divides them equally

among 18 bags. How many pounds of nuts are in each bag?
Mathematics
1 answer:
Nat2105 [25]3 years ago
5 0
7.20 pounds in each... IM SRRY IF WRONG
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Which of the following is an even function?
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The equation of the graphed line is x + 2y = 5. What is the x-intercept
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The x intercept is  -2y + 5

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3 years ago
A bank is reviewing its risk management policies with regards to mortgages. To minimize the risk of lending, the bank wants to c
Mariana [72]

Answer:

1. $ \mu = \$306,500 $

2. \sigma = \$24,500

3. n = 150

4. $ \mu_{x}= \mu = \$306,500 $

5. \sigma_x = \$ 2,000 \\\\

Step-by-step explanation:

The average mortgage owed by Americans is $306,500, with a standard deviation of $24,500.

From the above information, we know that,  

The population mean is

$ \mu = \$306,500 $

The population standard deviation is

\sigma = \$24,500

Suppose a random sample of 150 Americans is selected

n = 150

Since the sample size is quite large then according to the central limit theorem, the sample mean is approximately normally distributed.

The sample mean would be the same as the population mean  that is

$ \mu_{x}= \mu = \$306,500 $

The sample standard deviation is given by

\sigma_x = \frac{\sigma}{\sqrt{n} }

Where \sigma is the population standard deviation and n is the sample size.

\sigma_x = \frac{24,500}{\sqrt{150} }  \\\\\sigma_x = \$ 2,000 \\\\

Therefore, the required parameters are:

1. $ \mu = \$306,500 $

2. \sigma = \$24,500

3. n = 150

4. $ \mu_{x}= \mu = \$306,500 $

5. \sigma_x = \$ 2,000 \\\\

5 0
3 years ago
the admission fee for a charity event is 7 dollars for children and 10 dollars for adults the event was attended by 700 people a
ollegr [7]
Given:
$7/child
$10/adult
Total people = 700
Total money = $6,400

First, make two equations.
Let a = # of adults & Let c = # of children.
Let p = total people

1.      a+c = 700
2.  10a+7c = 6,400

Then, rearrange the equation to solve for a variable.
c = 700-a

Substitute (700-a) for c, or the # of children in the second equation.
10a+(700-a) = 6400
9a+700 = 6400
9a+700-700 = 6400-700
9a = 5700
9a/9 = 5700/9 
a = 633\frac{1}{3}  = # of adults attended

700-633\frac{1}{3} = c = 66 \frac{2}{3} = # of children attended


4 0
3 years ago
What is the center of the circle whose diameter has endpoints (18, -13) and (4, -3)?
jeka94

Answer:

Step-by-step explanation:

The center of the circle whose diameter has endpoints (18, -13) and (4, -3) will be the midpoint of the coordinates.

The ormua for calculating mid point is expressed as;

M(X,Y) ={(x21+x2/2, y1+y2/2}

X= x1+x2/2

Y = y1+y2/2

From the coordinates

x1 = 18 x2 = 4

X= 18+4/2

X = 22/2

X = 11

y1= -13, y2= -3

Y = -3-13/2

Y = -16/2

Y = -8

Hence the required centre will be at (11,-8)

4 0
3 years ago
Read 2 more answers
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