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Feliz [49]
3 years ago
7

What is the density of an object of an object having a mass of 6.0 grams and a volume of 35 cm3?

Chemistry
1 answer:
Marizza181 [45]3 years ago
8 0

Answer:

0.17 ( 2 s.f.)

Explanation:

d=m/v

=6/35

=0.1714285

=0.17

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An old 0.500 L lecture bottle of triethylamine (N(CH₂CH₃)₃) was found in a lab and needed for a synthesis reaction. A pressure r
Tatiana [17]

Mass of vaporized triethylamine : 2.606 g

<h3>Further explanation</h3>

Given

0.5 L triethylamine

P = 18.5 psi

T = 25 °C

Required

mass of vaporized triethylamine

Solution

Conversion :

P 18.5 psi = 1,26 atm

T = 25 +273 = 298 K

Ideal gas law :

PV=nRT

n = PV/RT

Input the value :

n = (1.26 atm x 0.5 L) /(0.08205 x 298)

n = 0.0258

MW triethylamine = 101 g/mol

Mass  triethylamine :

= n x MW

= 0.0258 x 101 g/mol

= 2.606 g

6 0
3 years ago
How does it’s atomic radius compare to chlorine’s?
Margarita [4]
I do not have a clue.
8 0
4 years ago
The half-life of thorium-227 is 18.72 days. How many days are required for three-fourths of a given amount to decay?
Pie
T½=18.72days
therefore t¾=18.72+½ of 18.72
we have 18.72+9.36=28.08days
7 0
3 years ago
4.50 g of NaCl reacts with 10.00 g of AgNO3 to produce 7.93 g of AgCl. If the theoretical amount of AgCl that can be formed is 8
olga nikolaevna [1]

Answer: 94.07%

Explanation:

Percentage yield can be calculated by the formula

%yield = Experimental yield/Theoretical yield x100

Experimental yield = 7.93g

Theoretical yield = 8.43

%yield = Experimental yield/Theoretical yield x100

%yield = 7.93/8.43 x 100 = 94.07%

4 0
3 years ago
Predict the products of the reaction below. that is, complete the right-hand side of the chemical equation. be sure your equatio
kkurt [141]
The equation is as follow,

<span>                                  HBr </span>₍aq₎  +  H₂O ₍l₎    →

Solution:
             HBr being strong acid with Ka value of 1.0 × 10⁹. When HBr is added to water, water acts as a base and HBr acts as a acid. Water picks the proton (H⁺) from HBr and converts into Conjugate acid (H₃O⁺) ahile HBr is converted into Conjugate Base (Br⁻) after loosing proton. The equation for this reaction is as follow,

                      HBr ₍aq₎  +  H₂O ₍l₎    →    H₃O⁺ ₍aq₎  +  Br⁻ ₍aq₎
8 0
3 years ago
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