For sodium, it has 1 valence electron
For oxygen, it has 6 valence electrons
For iron, it has 2 valence electrons
Answer:
Shift it toward the reactants.
Explanation:
From the reaction, the volume of the oxygen required is 89.6 L.
<h3>What is stoichiometry?</h3>
The term stoichiometry has to do with the process by which the mass of reactants or products in a reaction is obtained from the balanced reaction equation.
In this case, the balanced reaction is equation is;
CH₄ + 2 O₂ → CO₂ + 2 H₂O
Number of moles of CO2 = 88.0 g/44 g/mol = 2 moles
2 moles of O2 produced 1 mole of CO2
x moles of O2 produces 2 moles of CO2
X = 4 moles
1 mole of oxygen occupies 22.4 L hence 4 moles of oxygen occupies 4 * 22.4 L = 89.6 L
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Answer:
True.
Explanation:
When copper and nitrogen combine they formed the bond which is called ionic bond.
Ionic bond:
It is the bond which is formed by the transfer of electron from one atom to the atom of another element.
Both bonded atoms have very large electronegativity difference. The atom with large electronegativity value accept the electron from other with smaller value of electronegativity.
For example:
The electronegativity of nitrogen is 3.04 and that of copper is 1.9. Nitrogen required three electrons to complete the octet while copper loses its one valance electron to complete the octet. Thus when both combine nitrogen atom accept three electrons from three atoms of copper and form ionic bond. The compound formed is called copper nitride.
Cu₃N
Cu₃⁺³ N⁻³
The molar volume of a gas at STP occupies <u>22.4 L.</u>
Option D
<u>Explanation:</u>
To find the volume of 1 mole of a gas at STP, we use the Ideal Gas Law. It is the general gas equation which gives the relation to the measurable quantities to an ideal gas as below,
P (pressure) × V (volume) = n (number of moles) × R (the gas constant) × T (temperature in Kelvin)
STP = 1 atm of pressure and 273 K for temperature
P = 1 atm
V = ?
n = 1 mole
R = 0.0821 atm L/mol K
T = 273 K
Using the equation,
By substituting the above values, in the equation,
V = 22.38 L