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Art [367]
3 years ago
10

Of all the yoga students in a particular area, 20% study with Patrick and 80% study with Carl. We also know that 8% of the yoga

students study with Patrick and are female, while 66% of the students study with Carl and are female. What is the probability that a randomly selected yoga student is female, given that the person studies yoga with Carl?
A) .35
B) .56
C) .69
D) .83
Mathematics
1 answer:
Doss [256]3 years ago
8 0
P = \text{study with Patrick}
C = \text{study with Carl}
F = \text{female}

\mathbb P(F\mid C)=\dfrac{\mathbb P(F\cap C)}{\mathbb P(C)}=\dfrac{0.66}{0.80}=0.825\approx0.83
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