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Ierofanga [76]
3 years ago
6

What is the midpoint of (-1,5) (5,5)

Mathematics
1 answer:
mafiozo [28]3 years ago
5 0
(-1,5)(5,5)
midpoint formula : (x1 + x2)/2, (y1+ y2)/2

(-1 + 5)/2 , (5 + 5)/2) =
(4/2 , 10/2) =
(2,5) <===
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A ball dropped from a height of s feet takes t seconds to hit the ground, where t = . How much longer
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The answers is b. 1.06 seconds
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Will give brainiest if answered plz helpp!!!!!
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umm

Step-by-step explanation:

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3 years ago
Kerille is reading a book at the rate of 4.5 pages per minute. What ordered pair on a graph of his reading rate would represent
viva [34]
This is a linear equation y = mx, where:
m= slope or reading rate:
x = the number of minutes
y = the number of pages read.

So the equation becomes: y = 4.5.x
How many minutes it will take to read 90 pages (y):
90 = 4.5.x    or x = 90/4.5  and x = 20 minutes
So the ordered pair will be (20,90)



5 0
4 years ago
30. A box weighing 30 kilograms contains several
Yuri [45]

Answer:

Step-by-step explanation:

30 kg - 4.3 kg = 25.7 kg

25.7 kg - 0.4 kg = 25.3 kg

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There are 11 student books in the box.

6 0
3 years ago
El costo de producir 10 juegos de video al día es de 350 dólares , mientras que producir 30 juegos del mismo tipo al día cuestan
Dovator [93]

Answer:

El coste de producir un juego de vídeo es de 125 dólares.

Step-by-step explanation:

(This exercise is written in Spanish and is incomplete. Complete statement will be presented below)

El costo de producir 10 juegos de video al día es de 350 dólares , mientras que producir 30 juegos del mismo tipo al día cuestan 850 dólares . Si suponemos un modelo lineal como el descrito anteriormente , determine:

¿Cuál es el costo de producir un juego de vídeo?

(Explanation will be held in Spanish)

El modelo lineal es un polinomio de primer orden de la forma:

y = a\cdot x + b

Donde:

x - Variable independiente (eje x - Cantidad de juegos de vídeo producidos - Adimensional)

y - Variable dependiente (eje y - Coste de producción de juegos de vídeo - Dólares)

a - Pendiente de la función.

b - Intercepto en el eje y.

Dados los dos costes para dos cuotas distintas de producción, se construye el siguiente sistema de ecuaciones lineales:

10\cdot a + b = 350

30 \cdot a + b = 850

Se resuelve el sistema con algo de manipulación algebraica:

(30\cdot a + b) - (10\cdot a + b) = 850 - 350

20 \cdot a = 500

a = 25

Luego:

b = 850 - 30\cdot a

b = 100

La ecuación lineal es:

y = 25\cdot x +100

Finalmente, el coste de producir un juego de vídeo es:

y = 25 \cdot (1) + 100

y = 125

El coste de producir un juego de vídeo es de 125 dólares.

7 0
4 years ago
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