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Natasha2012 [34]

3 years ago

5

A single one celled organism divides into two identical cells every 30 minutes. If 6 of these organisms are present in a sample

now, how many will be present after 60 minutes(assuming none of them die)?

1 answer:

Nataly [62]3 years ago

6 0

We start with 6 organisms, whose population doubles every 30 minutes.
After 30 minutes we will have 12 and after 60 minutes we will have 24.

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Step-by-step explanation:

$x_{1} + x_{2} + x_{3} + x_{4} + x_{5} = 21\\$ (given)

Let us consider :

$x_{1}$ = $t_{1} + 1$

$x_{2}$ = $t_{2}$

$x_{3}$ = $t_{3}$

$x_{4}$ = $t_{4}$

$x_{5}$ = $t_{5}$

Now, by substituting the above considerations in the above equation, we get:

$t_{1} + 1 + t_{2} + t_{3} + t_{4} + t_{5} = 21\\$

$t_{1} + t_{2} + t_{3} + t_{4} + t_{5} = 20\\$

where,

$t_{i}$ $\geq$ 1

then it follows

n = 20

r = 4

then no. of solutions for the eqn = $_{r}^{n + r}\textrm{C}$

= $_{4}^{24}\textrm{C}$

= 10626

Answer :

no. of solutions for the eqn 10626

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