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LiRa [457]
3 years ago
9

(a^3b)^7(a^7b^7) simplify

Mathematics
1 answer:
Helen [10]3 years ago
5 0

Answer:

<h2>a²⁸b¹⁴</h2>

Step-by-step explanation:

\text{Use}\\\\(ab)^n=a^nb^n\\\\\bigg(a^n\bigg)^m=a^{nm}\\\\a^n\cdot a^m=a^{n+m}\\--------------------\\\\\bigg(a^3b\bigg)^7\bigg(a^7b^7\bigg)=\bigg(a^3\bigg)^7(b^7)(a^7)(b^7)=(a^{3\cdot7})(a^7)(b^7)(b^7)\\\\=\bigg(a^{21+7}\bigg)\bigg(b^{7+7}\bigg)=\boxed{a^{28}b^{14}}

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H(x) = 1/3x - 1 if h (15)
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f

∘

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h

∘

f

∘

g

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x

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f

∘

g

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(

x

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h

∘

f

∘

g

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(

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5 0
3 years ago
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andreev551 [17]

Answer:

{10}^{ - 14}

Step-by-step explanation:

\huge\frac{ {10}^{ - 9} }{ {10}^{5} }  \\  \\  \huge =  {10}^{ - 9}  \times  {10}^{ - 5}  \\  \\  \huge =  {10}^{ - 9  + ( - 5)}  \\  \\ \huge =  {10}^{ - 9 - 5}  \\  \\  \huge \orange {=  {10}^{ - 14}}

7 0
4 years ago
Read 2 more answers
Which statements are true about the trigonometric ratios of this triangle​
rosijanka [135]

Answer:

Options (1), (2), (3) and (4)

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By applying the sine and cosine rules in the given triangle,

sinθ = \frac{\text{Opposite side}}{\text{Hypotenuse}}

cosθ = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

cos(30°) = \frac{AC}{AB}

              = \frac{11\sqrt{3} }{22}

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sin(30°) = \frac{BC}{AB}

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             = \frac{1}{2}

cos(60°) = \frac{BC}{AB}

              = \frac{11}{22}

              = \frac{1}{2}

sin(60°) = = \frac{AC}{AB}

              = \frac{11\sqrt{3} }{22}

              = \frac{\sqrt{3}}{2}

Options (1), (2), (3) and (4) are the correct options.

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