Question

A researcher was interested in comparing the amount of time spent watching television by women and by men. Independent simple random samples of 14 women and 17 men were selected, and each person was asked how many hours he or she had watched television during the previous week. The summary statistics are as follows: Women Men _ Sample mean 12.9 hrs 16.4 hrs Sample SD 4.0 hrs 4.2 hrs Sample size 14 17 This sample data is then used to test the claim that the mean time spent watching television by women is less than the mean time spent watching television by men. Assume that the sample variances are equal, and a .05 significance level is used. What can we conclude from this test

Answer 1

Answer:

there is significant evidence to support that the claim that the mean time women spend watching television less than the mean time spent by men.

Step-by-step explanation:

H0 : μw = μm

H1: μw < μm

The test statistic :

(x1 - x2) / sqrt[(sp²/n1 + sp²/n2)]

df1 = 14 - 1 = 13

df2 = 17 - 1 = 16

Pooled variance = Sp² = (df1*s1² + df2*s2²) ÷ (n1 + n2 - 2)

Sp² = ((13*4^2) + (16*4.2^2)) ÷ (13 + 16)

Sp² = 16.90

t = (12.9 - 16.4) ÷ sqrt((16.90/14 + 16.90/17))

t = - 3.5 ÷ 1.4836645

t = - 2.359

Using the Pvalue from Tscore ; at 95% ; df = 29

Pvalue = 0.0126

Pvalue < α

0.0126 < 0.05 ;

Hence, we reject the null and conclude that there is significant evidence to support that the claim that the mean time women spend watching television less than the mean time spent by men.