Answer:
(b) Expected number of male kitten E(x) = 1
(c) Standard deviation is ±
.
Step-by-step explanation:
Given that,
Number of kittens in a group are 10. Out of these 5 are female.
To find:- (a) create a probability model of male kitten chosen.
So, total number of kitten = 10
number of female kitten = 5
then, Number of male kitten = 
Now total number of ways to choosing two kittens from group of 10 = 
= 
= 
for choosing (i) No male P(x=0) = P(Two female) = 
= 
(ii) 1 male P(x=1) = P(1 male and 1 female) =
=
=
(iii) 2 male P(x=2)= P(2 male) =
= 
0 1 2
P(X=
)

(b) what is expected number of male kittens chosen ?
Expected number of male kitten E(x) = 
= 
(c) what is standard deviation ?

No,

= 

= ± 