Since all you’re saying is evaluate ∫12–2
I’m assuming the answer would be 1/(1+x)(1-x)
Use the quadratic formula .
x^2-2x+11=0
a=1
b=-2
c=11
x=-2+- (-2)^2-4*1*11 divided by 2
x=2+- the square root of -40 divided by 2
There is no real solutions
By the remainder theorem 8x^2 + 4x - 3 when divided by 2x - 1 is
8(1/2)^2 + 4(1/2) - 3 = 2 + 2 - 3 = 1 answer
Answer:
2.3
Step-by-step explanation:
on the left side u add 4k+3k=7k
on the right side u subtract 2k-6k=4k
then on the left side u add 2 to each side and u get rid of the 2 on the left side
on the right side u add 5+2=7
then on the right side u add 4k on each side and get rid of the 4k on the right
on the left u subtract 7k-4k=3k
on both sides divide by 3
16) true
17) true
18) false
19) true
20) false
brainliest pls
