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solmaris [256]
3 years ago
6

EXTRA POINTS!

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
7 0

Answer:

y = 15

Step-by-step explanation:

angle poq + angle qor equals mpor (120)

4y + 3y + 15= 120

7y+15=120

subtract 15 from both sides

7y=150

divide both sides by 7

y=15

check:

4(15) + 3(15) + 15 equals 120

60 + 45 + 15 = 120

120 = 120

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Examine the method you used to estimate in the previous question. How does the estimate compare to the actual amount? Explain.
mr Goodwill [35]

Answer:

Step-by-step explanation:

Both $94 and 12% were rounded down, so the estimate will be less than the actual amount.

9 0
3 years ago
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A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

6 0
3 years ago
Please help me understand
puteri [66]

9514 1404 393

Answer:

  D.  86°

Step-by-step explanation:

Points D and F divide the circle into two arcs. The long arc is labeled 274°, and the short arc is the one you're asked to find. You know the total of these two arcs is the full circle, 360°.

  274° + DF = 360°

  DF = 360° -274°

  DF = 86°

__

There are other relationships you can use to find arc DF. One of the simpler ones is ...

  DF and the external angle at E are supplementary:

  DF = 180° -94° = 86°

5 0
3 years ago
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irinina [24]

Answer:

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