So, Anna has a markers, Ben has b markers and Cindy has c markers.
We know that a+b+c = m.
And we know also that a = 2b. (<span> twice as many markers as ben has</span>)
(Remember b is the number of Ben markers.)
The equation becomes:
2b+b+c=m.
Solving for c:
Cindy has (m-3b) markers.
Caillan's pocket money increased 20-15=5 dollars per week, or to 20-15=1.33 of it's original amount. This is a 33% increase.
Answer:
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Step-by-step explanation:
Answer:
Step-by-step explanation:
2 colours were taken
<h3>
Answer: Choice F) 1</h3>
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Explanation:
x^2+8x+7 factors to (x+1)(x+7)
x^2+4x-21 factors to (x-3)(x+7)
Therefore, the numerator (x^2+8x+7)(x-3) updates to (x+1)(x+7)(x-3)
The denominator (x^2+4x-21)(x+1) updates to (x-3)(x+7)(x+1)
We have three pairs of terms that will cancel between the numerator and denominator. The (x+1) terms pair up and cancel out, so do the (x+7) terms and also the (x-3) terms as well. Everything cancels out. The only thing left is 1 because x/x = 1 where x is nonzero. We can have a more complicated expression replace x to get the same basic idea. This is what I mean by "canceling".
