1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tino4ka555 [31]
2 years ago
13

he table represents an exponential function. A 2-column table has 4 rows. The first column is labeled x with entries 1, 2, 3, 4.

The second column is labeled y with entries 2, two-fifths, StartFraction 2 Over 25 EndFraction, StartFraction 2 Over 125 EndFraction. What is the multiplicative rate of change of the function? One-fifth Two-fifths 2 5
Mathematics
1 answer:
rusak2 [61]2 years ago
7 0

Exponential functions are defined as y = Abˣ, where b > 0 and b≠1. The multiplicative rate of change of the function is (1/5).

<h3>What is an exponential function?</h3>

Exponential functions are defined as y = Abˣ, where b > 0 and b≠1. As with every exponential equation, b is known as the base and x is known as the exponent. Bacterial growth is an example of an exponential function. Some germs multiply every hour.

An exponential equation is represented by y=Abˣ, given the table with the values, substitute the values from the first row we will get,

y=Abˣ

2=A x b¹

2 = Ab

A = 2/b

Now, substitute the values in the equation from the second row,

y=Abˣ

\dfrac{2}{5} = \dfrac{2}{b}  \times  b^2\\\\\dfrac{2}{5} = 2b\\\\b= \dfrac{1}{5}

Hence,  the multiplicative rate of change of the function is (1/5).

Learn more about Exponential Function:

https://brainly.in/question/15915245

#SPJ1

You might be interested in
Write the SLOPE-INTERCEPT FORM of the equation of the line through the given points by USING POINT-SLOPE FORM.
aivan3 [116]
When solving the slope you have to do this formula
y-y
2  1
------
x-x
2  1
The answer is -4/-5
3 0
3 years ago
What is 7539 increased by 3200
ddd [48]
Increased just means +
10739 is the sum
3 0
4 years ago
Mike hiked to a lake in 5.5 hours at an average rate of 2 1/5 miles per hour. Pedro hiked the same distance at a rate of 2 3/5 m
horrorfan [7]
Not sure whet da answer is but you’ll get it .
8 0
3 years ago
Read 2 more answers
The amount of money spent on textbooks per year for students is approximately normal.
Contact [7]

Answer:

(A) A 95% confidence for the population mean is [$332.16, $447.84] .

(B) If the confidence level in part (a) changed from 95% to 99%, then the margin of error for the confidence interval would increase.

(C) If the sample size in part (a) changed from 19 to 22, then the margin of error for the confidence interval would decrease.

(D) A 99% confidence interval for the proportion of students who purchase used textbooks is [0.363, 0.477]  .

Step-by-step explanation:

We are given that 19 students are randomly selected the sample mean was $390 and the standard deviation was $120.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                             P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean = $390

            s = sample standard deviation = $120

            n = sample of students = 19

            \mu = population mean

<em>Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ; </u>

P(-2.101 < t_1_8 < 2.101) = 0.95  {As the critical value of t at 18 degrees of

                                               freedom are -2.101 & 2.101 with P = 2.5%}  

P(-2.101 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.101) = 0.95

P( -2.101 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.101 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.101 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.101 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u> 95% confidence interval for</u> \mu = [ \bar X-2.101 \times {\frac{s}{\sqrt{n} } } , \bar X+2.101 \times {\frac{s}{\sqrt{n} } } ]

                        = [ \$390-2.101 \times {\frac{\$120}{\sqrt{19} } } , \$390+2.101 \times {\frac{\$120}{\sqrt{19} } } ]

                        = [$332.16, $447.84]

(A)  Therefore, a 95% confidence for the population mean is [$332.16, $447.84] .

(B) If the confidence level in part (a) changed from 95% to 99%, then the margin of error for the confidence interval which is Z_(_\frac{\alpha}{2}_) \times \frac{s}{\sqrt{n} } would increase because of an increase in the z value.

(C) If the sample size in part (a) changed from 19 to 22, then the margin of error for the confidence interval which is Z_(_\frac{\alpha}{2}_) \times \frac{s}{\sqrt{n} }  would decrease because as denominator increases; the whole fraction decreases.

(D) We are given that to estimate the proportion of students who purchase their textbooks used, 500 students were sampled. 210 of these students purchased used textbooks.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

                             P.Q.  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion students who purchase their used textbooks = \frac{210}{500} = 0.42    

            n = sample of students = 500

            p = population proportion

<em>Here for constructing a 99% confidence interval we have used a One-sample z-test statistics for proportions</em>

<u>So, 99% confidence interval for the population proportion, p is ; </u>

P(-2.58 < N(0,1) < 2.58) = 0.99  {As the critical value of z at 0.5%

                                               level of significance are -2.58 & 2.58}  

P(-2.58 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 2.58) = 0.99

P( -2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

P( \hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

<u> 99% confidence interval for</u> p = [ \hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

= [ 0.42 -2.58 \times {\sqrt{\frac{0.42(1-0.42)}{500} } } , 0.42 +2.58 \times {\sqrt{\frac{0.42(1-0.42)}{500} } } ]

= [0.363, 0.477]

Therefore, a 99% confidence interval for the proportion of students who purchase used textbooks is [0.363, 0.477]  .

8 0
3 years ago
After Friday's footbal game, Alana and her friends go out for ice cream. They share mega mountains sundae and finished the whole
Mrrafil [7]
What’s the question
6 0
3 years ago
Other questions:
  • Jessica has 4/8 of a bottle of Robitussin syrup on hand. The pharmacist instructs Jessica to reduce the syrup by 1/2 so he can p
    9·1 answer
  • Give a set of five integers, two positive and three negative, for which the mean, median, and mode are all -3
    7·1 answer
  • Helpeverything please urgent
    8·1 answer
  • Suppose A = {1, 2, 3, 4}. Let S and R be relations on A defined as follows:
    5·1 answer
  • Peter drives at a speed of 70 miles per hour.
    6·2 answers
  • Given f(x)=17-18, find x when f(x)=18
    7·1 answer
  • What is the cubic Yardage of a 60'X40'X6"<br> thick lab?
    12·1 answer
  • Can you plz help I don’t get it
    12·1 answer
  • Emma is 10 years old. she asked her father how old he is. her father answered, "when you are my age I will be 70." how old is Em
    11·2 answers
  • X + 3y = 10
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!