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tia_tia [17]
4 years ago
6

What is the greatest common factor of 18 and 72

Mathematics
2 answers:
Crazy boy [7]4 years ago
8 0
You need to find the common primes...

18=2*3*3  and 72=2*2*2*3*3  so they have 2*3*3 in common and 

2*3*3=18

So 18 is the greatest common factor.
lubasha [3.4K]4 years ago
4 0
Greatest Common Factor(GCF): Largest factor of two or more numbers

Factors of 18: 1, 2, 3, 6, 9, 18
Factors of 72: <span>1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

Largest number in both of the lists: 18

GCF: 18</span>
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Answer:

a) There is a 16.6% probability that doubles were rolled.

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Step-by-step explanation:

The probability formula is the number of desired outcomes divided by the number of total outcomes.

(a) Find the probability that doubles were rolled. (i.e. the two outcomes are equal)

There are six desired outcomes: (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)

There are 36 total outcomes. So:

P = \frac{6}{36} = 0.166

There is a 16.6% probability that doubles were rolled.

(b) Given that the roll resulted in a sum of 6 or less, find the conditional probability that doubles were rolled.

The following rolls result in a sum of 5 or less:

(1,1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (4,1), (4,2), (5,1)

So, there are 15 total outcomes.

3 of them are doubled: (1,1), (2,2), (3,3). So

P = \frac{3}{15} = 0.2

Given that the roll resulted in a sum of 6 or less, there is a 20% probability that doubles were rolled.

(c) Find the probability that at least one die is a 1

The following outcomes have at least one die that is 1:

(1,1), (1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(3,1),(4,1),(5,1),(6,1)

So, there are 11 desired outcomes out of 36.

P = \frac{11}{36} = 0.3055

There is a 30.55% probability that at least one die is a 1.

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