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nekit [7.7K]
3 years ago
14

Kirin is saving money to enter a craft fair with his new jewelry business. The entry fee is $150. He sells bracelets for $4 each

and he has saved up $36. so far. What is the least number of bracelets he would need to sell to afford the entry fee?​
Mathematics
2 answers:
GaryK [48]3 years ago
8 0

Answer:

29 bracelet

Step-by-step explanation:

150-36=114

114÷4=28.5≈29

valkas [14]3 years ago
6 0

Answer:7

Step-by-step explanation:

36 is his saved up starting point.

needed total is 150. 150-36=114

$4 per bracelet, so 114/4= $28.50/4= 7.

He needs to sell 7 more to get to 28.50 for the added total of 150.

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\qquad\qquad\huge\underline{{\sf Answer}}♨

Let's solve ~

Assume width of rectangle be " x ", length = 3×width + 8 = 3x + 8 ~

Now, Perimeter of rectangle is :

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\qquad \sf  \dashrightarrow \:4x + 8  = 56 \div 2

\qquad \sf  \dashrightarrow \:4x + 8  = 28

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\qquad \sf  \dashrightarrow \:x = 20\div 4

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\qquad \sf  \dashrightarrow \:l = 3w + 8

\qquad \sf  \dashrightarrow \:l = 3(5)+ 8

\qquad \sf  \dashrightarrow \:l = 15+ 8

\qquad \sf  \dashrightarrow \:l =23 \:cm

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3 years ago
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