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yuradex [85]
3 years ago
6

Express 3a^2 b^ -1 with positive exponents

Mathematics
2 answers:
Brums [2.3K]3 years ago
8 0
<span>3a^2 b^ -1 
= 3a^2b

hope it helps</span>
choli [55]3 years ago
5 0

Answer: Simplified form in positive exponents is \dfrac{3a^2}{b}

Step-by-step explanation:

Since we have given that

3a^2b^{-1}

We need to write with positive exponents:

As we know that

a^{-1}=\dfrac{1}{a}

So, it becomes,

3a^2b^{-1}=\dfrac{3a^2}{b}

Hence, simplified form in positive exponents is \dfrac{3a^2}{b}

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Select the Like Terms in this expression
sesenic [268]

Answer:

5, 2x2 and 4

Step-by-step explanation:

Terms are expressions or characters that are separated by a plus or minus sign.

therefore, the terms are 3x, 5, 2x2 and 4

like terms have the same have the same variables or no variables attached to them.

like terms = 5, 2x2, and 4

Note: 2x2 = 4

8 0
3 years ago
I need help with solving this problem please!!!
KATRIN_1 [288]
3 is 23 degree
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3 years ago
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asambeis [7]
C. Hope this helps:)
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On Novermber 27, 1993, the New York times reported that wildlife biologists have found a direct ink between the increase in the
Korolek [52]

Answer:

a.  1 263 888

b. 130 701

c. 72 years

Step-by-step explanation:

a. The differential equation applies here.

Let the quantity increase for a certain time be given by Q(t)

Every unity of time, the quantity increases by 1+\frac{r}{100} so that after the time t, the quantity remaining will be given by:

Q(t) = (1+ \frac{r}{100} )^{t}

In a similar manner, the quantity R(t) decreases at a rate given by the following expression:

1-\frac{r}{100} and after the time , t the quantity of R remaining will be given by:

R(t) = (1-\frac{r}{100} )^{t}

a. To find the population of humans in 1953

Q(t) = (1+ \frac{r}{100} )^{t}

1993 - 1953 = 40 years = t

Q(40) = Q×1.06^{40}

Q = 1 263 888.44

    ≈ 1 263 888

b. For bear population in 1993:

R(t) = (1-\frac{r}{100} )^{t}

t = 40

R(40) = b 0.94^{40} = 11 000

b = 130 700. 889

    ≈130 701

c. time taken for black bear population number less than 100 is given by:

130 = 11000×0.94^{t}

solving using natural logarithms gives t = 72.72666

                                                                  =   72 years Ans

8 0
3 years ago
6g + 12 =<br> Help help help help help
dimaraw [331]

Answer:

I need more information cause to solve that in simplest form it would be

6G + 12

Step-by-step explanation:

5 0
3 years ago
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