Question

I will give the brainliest thank you

Answer 1

Answer:

x=8, $y=8 \sqrt2$

Step-by-step explanation:

Consider the given right triangle,

As, $\tan \Theta = \frac{Perpendicular}{Base}$

Consider $\tan 45^{\circ}=\frac{x}{8}$

$1=\frac{x}{8}$

So, x=8

As, $\sin \Theta = \frac{Perpendicular}{Hypotenuse}$

Consider $\sin 45^{\circ}=\frac{8}{y}$

$\frac{1}{\sqrt2}=\frac{8}{y}$

So, $y=8 \sqrt2$

Therefore, x = 8 and $y=8 \sqrt2$

Answer 2

Answer:

option 2

Step-by-step explanation:

in the given triangle,

tan45° = 8/x

=> 1 = 8/x

=>x = 8

for y,

cos45° = 8/y

=>1/√2 = 8/y

=>y = 8√2