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wariber [46]
4 years ago
14

Which of the following points is a valid solution for the inequality

Mathematics
2 answers:
Ksju [112]4 years ago
4 0

Answer:

The points that are solution of inequality are:

(2,5) and (-1,-4).

Step-by-step explanation:

Clearly from the graph we could see that :

  • The line does not pass through (0,0).

        Hence (0,0) is not a solution of the system.

  • Also at x=2 the line passes through the point 5.

       Hence, (2,5) is a solution for the inequality

  • At x=1, the line passes through the point y=2

        Hence, (1,-1) is not a solution for the inequality.

  • At x=-1 the graph passes through y=-4.

        Hence, (-1,-4) is a solution of the inequality.


Ierofanga [76]4 years ago
3 0

Answer:

(1,-1) is a valid solution for the inequality.

Step-by-step explanation:

Given the graph of function we have to find the solution for inequality

Lets take the two points passing through the graph let it be (1,2) and (2,5).

Equation of line passing through the above two points are

(y-y')=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} (x-x')

(y-2)=\frac{5-2}{2-1}(x-1)

⇒ y-2=3(x-1)

⇒ 3x-y=1

To find the inequality equation, put any point which comes in shaded region to above equation and put the sign of that inequality which gives the true condition. (3x-y=3(1)-0=3>1)

Hence, the inequality becomes 3x-y>1

To find the valid solution put the points one by one in above inequality and get the result.

(0,0) : 3(0)-0=0>1,   False

(2,5) : 3(2)-5=1>1,  False

(1,-1) : 3(1)-(-1)=4>1, True

(-1,-4) : 3(-1)-(-4)=1>1,  False

Hence, (1,-1) is a valid solution for the inequality



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3 years ago
Vaimiti walks at a constant pace of 1.1 m/s and takes 25 minutes to get to school.
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Solution:

<u>Note that:</u>

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  • Vaimiti speed = 1.1 m/s
  • Jabril speed = 1.3 m/s

<u>Converting the time (minutes to seconds) for Vaimiti to reach school:</u>

  • Vaimiti's time to reach school: 25 minutes = 25 x 60 seconds
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<u>Converting the time (minutes to seconds) for Jabril to reach school:</u>

  • Jabril's time to reach school: 30 minutes = 30 x 60 seconds
  • => Jabril's time to reach school: 1800 seconds

<u>Finding the distance of Vaimiti:</u>

  • Speed = Distance/Time

Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>

  • => 1.1 meters/second = Distance/1500
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  • => 1650 meters = Distance (In meters)

<u>Finding the distance of Jabril:</u>

  • Speed = Distance/Time

Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>

  • 1.3 meters/second = Distance (In meters)/1800 seconds
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  • => 2340 meters = Distance (In meters)

This can lead to two possible solutions:

Possible solution #1:

<u>Finding the difference between the two distances:</u>

  • 2340 meters - 1650 meters = Difference (In meters)
  • => 690 meters

Possible solution #2:

The difference between the <u>distances they walked</u> is that Jabril walked <u>faster</u> than Vaimiti, but Vaimiti reached <u>school</u> earlier than Jabril because the <u>walking distance</u> for Vaimiti is less than the <u>walking</u> <u>distance</u> for Jabril.

Hoped this helped!

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