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3 years ago

If i had a kid on october 6th and another 12 months later how old would the first kid be

Mathematics

2 answers:

Monica [59]3 years ago

7 0

Answer- If you mean of 2021 for the first he would be he would just turn 1 yrs old

Explain- October 6 2021 + 12 months = Wednesday October 6.

Extra- they would both have the same birthday but for different years. 12 months equals 1 year.

zepelin [54]3 years ago

5 0

Answer:

3 months old

Step-by-step explanation:

9 months for birth

and then the other 3 months is the age.

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10-x-3x=7x-23<br> I need help with this question it is too hard

charle [14.2K]

X=3

10- 4x=7x-23
14x-7x=123-10
-11x=-23-10
11x=-33÷(-11)
x=3

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4 years ago

Please only answer 6.

Illusion [34]

Answer:

Use keep change flip And narrow down to a simplest anwser

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3 years ago

Team A and team B play a series. The first team to win three games wins the series. Each team is equally likely to win each game

andrezito [222]

Answer:

Probability is $\frac{1}{4}$

Step-by-step explanation:

This problem can be easily done tree diagram.

Few things keep in mind :

From starting of match three victories of A.
Less then or equal to two victories of B.
In each matches there are two possibilities either favourable for A or B.

First case if A wins first match

two victories of B then two of A
victory of B then A then B then A
victory of B then A then A

Second case if B wins first match(favorable)

victory of two B then three A

So total cases are 4 and favorable is one

probability= $\frac{1}{4}$

[Tree diagram is in attachment]

7 0

4 years ago

I need help someone

NeX [460]

I believe the answer is b

4 0

3 years ago

A circular pond is modeled by the equation x^2 + y^2= 225. A bridge over the pond is modeled by a segment of the equation x – 7y

serious [3.7K]

$x^2+y^2=225 \\
x-7y=-75 \\ \\
\hbox{solve the second equation for x:} \\
x-7y=-75 \ \ \ |+7y \\
x=7y-75 \\ \\
\hbox{substitute 7y-75 for x in the first equation:} \\
(7y-75)^2+y^2=225 \\
49y^2-1050y+5625+y^2=225 \\
50y^2-1050y+5625=225 \ \ \ \ \ \ \ \ \ |-225 \\
50y^2-1050y+5400=0 \ \ \ \ \ \ \ \ \ \ \ \ |\div 50 \\
y^2-21y+108=0 \\
y^2-9y-12y+108=0 \\
y(y-9)-12(y-9)=0 \\
(y-12)(y-9)=0 \\
y-12=0 \ \lor \ y-9=0 \\
y=12 \ \lor \ y=9$

$x=7y-75 \\
x=7 \times 12 -75 \ \lor \ x=7 \times 9-75 \\
x=84-75 \ \lor \ x=63-75 \\
x=9 \ \lor \ x=-12 \\ \\
(x,y)=(9,12) \hbox{ or } (x,y)=(-12,9)$

The points are (9,12) and (-12,9).
The answer is A.

7 0

3 years ago