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3 years ago

Simplify 12x^4 ÷ 4x^3

Mathematics

1 answer:

Soloha48 [4]3 years ago

7 0

Answer:

=3x^7

Step-by-step explanation:

Simplify, 12x^4 ÷ 4 x^3

Cheers! :)

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Find the value of Y! please help

Maurinko [17]

Answer:

y = 5.6

Step-by-step explanation:

Use Sine

Sine = $\frac{opposite}{hypothenuse}$

Sine 45 = $\frac{y}{18}$

Sine of 18 is 0.309

0.309 = $\frac{y}{18}$

Multiply 18 on both sides

0.309 x 18 = $\frac{y}{18}$ x 18

5.562 = y

Round to the nearest tenth:

5.562 = 5.6

3 0

2 years ago

Which of the following is a nonlinear function

pogonyaev

Answer:

Linear functions are equations where the greatest power of the variable (typically x) is 1;

They are graphed as straight lines;

So, any function that has the following format:

f(x) = ax + b;

Nonlinear functions would be any equation that has a variable to a power greater than 1;

This could be a quadratic equation or an exponential equation

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1 year ago

Write the perimeter of the triangle in simplest form<br><br> can i please get help

Zepler [3.9K]

This is easy. You just add all the like terms

8 0

2 years ago

Match each point with one of the following fractions: 5/6, 7/12, 1/8, 5/16

adelina 88 [10]

I do not know what point is you trying to find

4 0

3 years ago

Could someone help me rnnn?

GuDViN [60]

Answer:

vertex = (0, -4)

equation of the parabola: $y=3x^2-4$

Step-by-step explanation:

Given:

y-intercept of parabola: -4
parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola: $y=a(x-h)^2+k$

(where (h, k) is the vertex and $a$ is some constant)

Substitute point (0, -4) into the equation:

$\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}$

Substitute point (-2, 8) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}$

Substitute point (1, -1) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(1.-1) \implies a(1-h)^2+k &=-1\\a(1-2h+h^2)+k &=-1\\a-2ah+ah^2+k &=-1\\\implies a-2ah-4&=-1\\a(1-2h)&=3\end{aligned}$

Equate to find h:

$\begin{aligned}\implies a(1+h) &=a(1-2h)\\1+h &=1-2h\\3h &=0\\h &=0\end{aligned}$

Substitute found value of h into one of the equations to find a:

$\begin{aligned}\implies a(1+0) &=3\\a &=3\end{aligned}$

Substitute found values of h and a to find k:

$\begin{aligned}\implies ah^2+k&=-4\\(3)(0)^2+k &=-4\\k &=-4\end{aligned}$

Therefore, the equation of the parabola in vertex form is:

$\implies y=3(x-0)^2-4=3x^2-4$

So the vertex of the parabola is (0, -4)

5 0

2 years ago

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