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levacccp [35]
3 years ago
6

Decide whether each expression is equal to 6 x 3/4. Write an X in the table to respond.

Mathematics
1 answer:
Tomtit [17]3 years ago
5 0

Answer:

6 × ¼ is NOT EQUAL TO 6 × ¾

8 × ²/4 is NOT EQUAL TO 6 × ¾

18/(2 × 2) is EQUAL TO 6 × ¾

Step-by-step explanation:

Given 6 * ¾,

We're asked to determine if each of the given expressions is equal or not equal to 6 * ¾.

Let's evaluate 6 * ¾

6 × ¾ = (6×3)/4 = 18/4 = 4.5

Now, let's compare each expression given to determine if it is equal or not

✔️6 × ¼ = (6×1)/4 = 6/4 = 1.5

Therefore,

6 × ¼ is NOT EQUAL TO 6 × ¾

✔️8 × ²/4 = (8×2)/4 = 16/4 = 4

Therefore,

8 × ²/4 is NOT EQUAL TO 6 × ¾

✔️18/(2 × 2) = 18/4 = 4.5

Therefore,

18/(2 × 2) is EQUAL TO 6 × ¾

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Please explain how to do this.
damaskus [11]

Step-by-step explanation:

let the eqn be y = mx + b.

m = 200/(900 - 700) = 1

sub (700, 0):

0 = 700 + b

b = -700

therefore eqn is y = x - 700

Topic: coordinate geometry

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5 0
3 years ago
Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
3 years ago
Drag the values to order them from least to greatest, with the least at the top.
sergiy2304 [10]

Answer:

√143

4π

√79+√63

Step-by-step explanation:

√143 gives 11.958

4π = 4 times 22/7 = 12.57

√79+√63 gives 16.825

In ascending order, i.e from the least to the greatest, we have

11.958

12.57

16.825

Which is same as

√143

4π

√79+√63

3 0
4 years ago
Factor completely.
erik [133]
(n-4)(n+11) so pretty much B
3 0
3 years ago
A.(4,0)<br>B.(0,0)<br>C.(-2,0)​
ra1l [238]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
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