We have the sample size, sample mean and the sample standard deviation. Since the population standard deviation is not know, we will use t-distribution to find the confidence interval.

The critical t value for 95% confidence interval and 63 degrees of freedom is 1.998.

The 95% confidence for the population mean will be:

$(119-1.998 *\frac{16}{ \sqrt{64} } ,119+1.998 *\frac{16}{ \sqrt{64} }) \\ \\ 
=(115.004, 122.996) \\ \\=(115,123)$

Thus, the 95% confidence interval for the population mean will be (115,123)

So, option A is the correct answer

6 0

3 years ago

Write three measurments using grams and three measurements using milligrams total 15.4 grams

luda_lava [24]

2+3+10 g +1+1+2mg =15.4 grams

5 0

3 years ago

Can someone pls tell me the answer

sleet_krkn [62]

Answer:

Part a is c and part b is d

Step-by-step explanation: