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skad [1K]
3 years ago
14

At 9:00, Paula has x cups of food in a container for her dog. Paula pours a 2 1/2 cup box of food into the container. Then she r

emoves 3/4 cup of food to feed her dog. Now there are 5 1/4 cups of food in the container.
write an equation that can be used to determine the number of cups, x, of food in the container at 9:00?

Which equation can be used to determine the number of cups of food, x, in the container at 9:00?

A.5 1/4 = x + 212 + 34
B.5 1/4 = x − 212 + 34
C.5 1/4 = x + 212 − 34
D.5 1/4 = x − 212 −34
Mathematics
2 answers:
pishuonlain [190]3 years ago
6 0

Answer:

i think a

Step-by-step explanation:

77julia77 [94]3 years ago
6 0

Answer:

c correct me if wrong though.

Step-by-step explanation:

c is 5 1/4 = x + 2 1/2 − 3/4 [ but if it is actually 212 and 34, then none of them are right. i'm just putting the division sign where i thought it should be coming off from the problem. ]

the reason why i said c is because on how it adds 2 and 1/2 cups <u>INTO</u> the container, meaning that there will be x + 2 1/2 amount of food in the container. then, <u>REMOVING</u> 3/4 cups out of the container would mean that we have to subtract it. so −3/4.

feel free to correct me if needed.

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8 0
3 years ago
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umka2103 [35]

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B&gt;13/9 interval notation
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3 0
3 years ago
Mr lim had 3kg of sugar . He divided the sugar into 5 equal amounts.what is the mass of eacy amount of sugar give your answer as
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6 0
4 years ago
A company’s profit in dollars is modeled by the equation p(x) = –0.5x2 + 100x, where x represents the number of units sold.
serg [7]

Answers:

a. The company needs to sell 100 units to reach the maxmum profit.

b. The company's maximum profit is $5,000.

Solution:

a. How many unit does the company need to sell to reach the maximum profit?

p(x)=-0.5x^2+100x

This is a quadratic equation, and its graph is a parabola vertical (because the veriable "x" is square). Comparing with the general form:

p(x)=ax^2+bx+c; a=-0.5, b=100, c=0

a=-0.5<0 (negative), then the parabola opens downward, and it has a maximimun value (maximum profit) at its vertex.

We can find the abscissa of the vertex (units that the company needs to sell to reach the maximum profit using the following formula:

x=-b/(2a)

Replacing b by 100 and a by -0.5 in the formula above:

x=-100/[2(-0.5)]

x=-100/(-1)

x=100

The company needs to sell 100 units to reach the maximum profit.


b. What's the company's maximum profit?  

To determine the maximum profit we substitute the value of "x" obrained in part "a" in the quadratic equation:

x=100→p(100)=-0.5(100)^2+100(100)

p(100)=-0.5(10,000)+10,000

p(100)=-5,000+10,000

p(100)=5,000

The company's maximum profit is $5,000.

6 0
3 years ago
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