Sorry, i wish i could help, but really the only thing i know is that 4 is 2 by 2 so using another equation to try to prove otherwise is irrational in itself
Answer:
Step-by-step explanation:
I can't see
Answer:
B: y = − (x − 3)² + 2
Step-by-step explanation:
You can check this using a graphing calculator, but it has a vertex of (3,2)
Split the second term in 9s^2 - 36s + 35 into two terms
9s^2 - 15s - 21s + 35
Factor out common terms in the first two terms, then in the last two terms
3s(3s - 5) - 7(3s - 5)
Factor out the common term 3s - 5
<u>(3s - 5)(3s - 7) </u>
Explanation:
A sequence is a list of numbers.
A <em>geometric</em> sequence is a list of numbers such that the ratio of each number to the one before it is the same. The common ratio can be any non-zero value.
<u>Examples</u>
- 1, 2, 4, 8, ... common ratio is 2
- 27, 9, 3, 1, ... common ratio is 1/3
- 6, -24, 96, -384, ... common ratio is -4
___
<u>General Term</u>
Terms of a sequence are numbered starting with 1. We sometimes use the symbol a(n) or an to refer to the n-th term. The general term of a geometric sequence, a(n), can be described by the formula ...
a(n) = a(1)×r^(n-1) . . . . . n-th term of a geometric sequence
where a(1) is the first term, and r is the common ratio. The above example sequences have the formulas ...
- a(n) = 2^(n -1)
- a(n) = 27×(1/3)^(n -1)
- a(n) = 6×(-4)^(n -1)
You can see that these formulas are exponential in nature.
__
<u>Sum of Terms</u>
Another useful formula for geometric sequences is the formula for the sum of n terms.
S(n) = a(1)×(r^n -1)/(r -1) . . . . . sum of n terms of a geometric sequence
When |r| < 1, the sum converges as n approaches infinity. The infinite sum is ...
S = a(1)/(1-r)
