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3 years ago

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Factor 9s^2 - 36s + 35

1 answer:

Verdich [7]3 years ago

4 0

Split the second term in 9s^2 - 36s + 35 into two terms

9s^2 - 15s - 21s + 35

Factor out common terms in the first two terms, then in the last two terms

3s(3s - 5) - 7(3s - 5)

Factor out the common term 3s - 5

<u>(3s - 5)(3s - 7) </u>

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How to do this question plz answer me

Sati [7]

Answer:

$d = \frac{4 - 3c}{c + 1}$

Step-by-step explanation:

To make d the subject of formula, we need to rearrange the equation such that we arrive at d= _____.

$c = \frac{4 - d}{d + 3}$

<em>Remove the fraction by multiplying (d +3) on both sides:</em>

$c(d + 3) = 4 - d$

<em>Expand</em><em>:</em>

<em> $cd + 3c = 4 - d$ </em>

<em>Bring</em><em> </em><em>all</em><em> </em><em>the</em><em> </em><em>d</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>one</em><em> </em><em>side</em><em> </em><em>and</em><em> </em><em>move</em><em> </em><em>the</em><em> </em><em>others</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em> </em><em>side</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>equation</em><em>:</em>

$cd + d = 4 - 3c$

<em>Factorise</em><em> </em><em>d</em><em> </em><em>out</em><em>:</em>

<em> $d(c + 1) = 4 - 3c$ </em>

<em>Divide</em><em> </em><em>by</em><em> </em><em>(</em><em>c</em><em> </em><em>+</em><em>1</em><em>)</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>

<em> $d = \frac{4 - 3c}{c + 1}$ </em>

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3 years ago

How many zeros are there in the standard form of six hundred thousand, twenty?

Julli [10]

There are Three zeros

3 0

3 years ago

A market surveyor wishes to know how many energy drinks teenagers drink each week. They want to construct a 98% confidence inter

frosja888 [35]

Answer:

The minimum sample size required to create the specified confidence interval is 1024.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.98}{2} = 0.01$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.01 = 0.99$ , so $z = 2.327$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to create the specified confidence interval

This is n when $M = 0.08, \sigma = \sqrt{1.21} = 1.1$ .

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.08 = 2.327*\frac{1.1}{\sqrt{n}}$

$0.08\sqrt{n} = 2.327*1.1$

$\sqrt{n} = \frac{2.327*1.1}{0.08}$

$(\sqrt{n})^{2} = (\frac{2.327*1.1}{0.08})^{2}$

$n = 1024$

The minimum sample size required to create the specified confidence interval is 1024.

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4 years ago

NEED HELP ASAP.<br> Check my answer

lisabon 2012 [21]

that looks like a regular octagon to me

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4 years ago

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Tiana's Cafe offers two kinds of espresso: single-shot and double-shot. Yesterday afternoon, the cafe sold 50 espressos in all,

Step2247 [10]

Answer:

I am pretty sure its 43.48%

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3 years ago