Question

Find the point on the graph of y=x^2 where the tangent line has slope m= - 1/3

Answer 1

Here the graph y=x²

Taking the 1st derivative here of the y it will be

y1 = 2x

m=-1/3

That is m=2x

so x=-1/6

so y=(-1/6)²=1/36

So the coordinate of point will be=(-1/6 , 1/36)