Find the point on the graph of y=x^2 where the tangent line has slope m= - 1/3
1 answer:
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Y = 5x + 2
y = 3x
5x + 2 = 3x
- 5x - 5x
2 = -2x
-2 - 2
-1 = x
y = 3x
y = 3(-1)
y = -3
(x, y) = (-1, -3)
y = 3x
5x + 2 = 3x
- 5x - 5x
2 = -2x
-2 - 2
-1 = x
y = 3x
y = 3(-1)
y = -3
(x, y) = (-1, -3)
To convert our number to scientific notation, we are going to move the decimal point to the right until we have only one non-zero digit to the left of the decimal point, and then, we are going to multiply that number by a negative power of 10 equal to the number of times we moved the decimal point to the right:
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Our number is 0.000000016, so we need to move the decimal point 8 times to the right to have </span>only one non-zero digit to the left of the decimal point (1.6). Since we moved the decimal point eight times to the right, we are going to multiply 1.6 by y a negative power of 10 equal to the number of times we moved the decimal point to the right i.e.
.
So 0.000000016 expressed in scientific notation is 1.6x
, or in calculator notation 1.6E-8
We can conclude that the correct answers are <span>1.6E-8 and </span><span>1.6 × 10-8</span>
<span>
Our number is 0.000000016, so we need to move the decimal point 8 times to the right to have </span>only one non-zero digit to the left of the decimal point (1.6). Since we moved the decimal point eight times to the right, we are going to multiply 1.6 by y a negative power of 10 equal to the number of times we moved the decimal point to the right i.e.
So 0.000000016 expressed in scientific notation is 1.6x
We can conclude that the correct answers are <span>1.6E-8 and </span><span>1.6 × 10-8</span>