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USPshnik [31]
3 years ago
12

Alisha is conducting a paired differences test for a "before (B score) and after (A score)" situation. She is interested in test

ing whether the average of the "before" scores is higher than that of the "after" scores.
(a) To use a right-tailed test, how should Alisha construct the differences between the "before" and "after" scores?
(b) To use a left-tailed test, how should she construct the differences between the "before" and "after" scores?
Mathematics
1 answer:
madreJ [45]3 years ago
5 0

Answer:

Step-by-step explanation:

The question says that Alisha is interested in testing whether the average (mean) of the B scores is GREATER THAN the average of the A scores.

Normally, a right-tailed test is used to conduct such experiment because Alisha is comparing in the positive - greater than.

Since we weren't given any figures in the question, we'll use algebra.

Hence,

Let the mean of the B scores be X

and the mean of the A scores be Y

(A) In this case, Alisha wants to know if X is greater than Y. She'll construct the difference between both means thus:

Null hypothesis: X is greater than Y

Alternative hypothesis: X is not greater than Y

Remember that the null hypothesis is the fact which the researcher is testing or which he/she wants to ascertain or prove WHILE the alternative hypothesis is the negating event.

(B) For a left-tailed test to be conducted, Alisha's research statement will be rephrased thus:

Alisha is interested in testing whether the average of the A scores is LESS THAN the average of the B scores.

The hypothesis statement will now be:

Null hypothesis: Y is less than X

Alternative hypothesis: Y is not less than X

As the distinction between both types of hypothesis test has been established, in each case, succeeding statistical-analysis steps are the same.

Alisha can then perform her regression analysis with the numerical data given.

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Allisa [31]

Answer:

The probability of Steve agreeing with the company’s claim is 0.50502.

Step-by-step explanation:

Let <em>X</em> denote the number of green candies.

The probability of green candies is, <em>p</em> = 0.20.

Steve buys 30 bags of 30 candies, randomly selects one candy from each, and counts the number of green candies.

So, <em>n</em> = 30 candies are randomly selected.

All the candies are independent of each other.

The random variable <em>X</em> follows a binomial distribution with parameter <em>n</em> = 30 and <em>p</em> = 0.20.

It is provided that if there are 5, 6, or 7 green candies, Steve will conclude that the company’s claim is correct.

Compute the probability of 5, 6 and 7 green candies as follows:

P(X=5)={30\choose 5}(0.20)^{5}(1-0.20)^{30-5}=0.17228\\\\P(X=6)={30\choose 6}(0.20)^{6}(1-0.20)^{30-6}=0.17946\\\\P(X=7)={30\choose 7}(0.20)^{7}(1-0.20)^{30-7}=0.15328

Then the probability of Steve agreeing with the company’s claim is:

P (Accepting the claim) = P (X = 5) + P (X = 6) + P (X = 7)

                                       = 0.17228 + 0.17946 + 0.15328

                                       = 0.50502

Thus, the probability of Steve agreeing with the company’s claim is 0.50502.

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AVprozaik [17]

Answer:

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Step-by-step explanation:

From the question we are told that

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   The number that believe there was a conspiracy is  k = 614

Generally the sample proportion is mathematically represented as

      \^ p =  \frac{614}{1057 }

=>   \^ p = 0.5809

From the question we are told the confidence level is  95% , hence the level of significance is    

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Generally the margin of error is mathematically represented as  

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=>    0.5809 - 0.02975<  p <  0.5809 + 0.02975

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Answer:

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