All categories

3 years ago

Convey 90 cubic feet into cubic yards

Mathematics

1 answer:

nignag [31]3 years ago

5 0

There are 3 feet in 1 yard, so 90/3 = x cubic yards

x = 30

30 cubic yards is your answer

hope this helps

You might be interested in

D. Please and explain

aleksandr82 [10.1K]

What is 1 divided by 5? Answer is .2. Then do .2 times 100

6 0

3 years ago

HELP WILL MARK BRAINLIEST <br> If the sin 60° is

uranmaximum [27]

The answer is the 3rd option

30-60-90 triangle for reference

Remember soh cah toa

O:opposite, a:adjacent, h:hypotenuse

S:sin c:cosine t:tangent

Hope this helped :)

4 0

3 years ago

Read 2 more answers

HELP PLZ<br> How does the graph of a linear inequality differ from the graph of a linear equation?

musickatia [10]

Answer:

Step-by-step explanation:

The main difference in the graph of a linear inequality is that we shade (darken) an area on one side or the other of the line. We draw that line as a solid line in cases where ≤ or ≥ are involved; otherwise we draw a dashed line for cases involving < or >.

6 0

3 years ago

Which of the following expressions represents the verbal description below?

Georgia [21]

Cube of the sum of 4 and 9 times x means (4+9x)^3
Product of 5times x and the difference of x and 1 means 5x(x-1)

Lets divide

Expression is

$\\ \sf\longmapsto \dfrac{(4+9x)^3}{5x(x-1)}$

5 0

3 years ago

Read 2 more answers

A long-jumper lifts off 3 m after starting his run, and lands 6 m later. When he is 8 m from the start line, he is 5 cm above th

Alexeev081 [22]

Answer:

The equation of the parabola that models the path of the long jumper through the air is $y = -x^{2} +12$ × $x-27$

Step-by-step explanation:

Mathematically, we know that parabolas are second-order polynomials and every second-order polynomials, also known as quadratic functions, can be constructed by knowing three different points of the curve. The standard form of the parabola is:

$y = a$ × $x^{2} +b$ × $+ C$

Where:

x - Horizontal distance from the start line, measured in meters.

y - Height of the long jumper, measured in meters.

a,b,c - Polynomial constants, measured in $\frac{1}{m}$ , dimensionless and meters, respectively.

If we know that $(x_{1},y_{1}) = (3\,m, 0\,m), (x_{2},y_{2}) = (8\,m, 0.05\,m)$ and $(x_{3}, y_{3}) = (9\,m, 0\,m),$ this system of linear equations is presented below:

$9\cdot a + 3\cdot b + c = 0 (Eq. 1)81\cdot a + 9\cdot b + c = 0 (Eq. 2)64\cdot a + 8\cdot b + c = 0.05 (Eq. 3)$

The coefficients of the polynomial are, respectively:

$a = -\frac{1}{100}, b = \frac{3}{25}, c = -\frac{27}{100}$

The equation of the parabola that models the path of the long jumper through the air is $y' = -\frac{1}{100}\cdot x^{2}+\frac{3}{25}\cdot x -\frac{27}{100}.$

But we need y measured in centimeters, then, we use the following conversion:

$y = 100\cdot y'$

Then, we get that:

$y = -x^{2}+12\cdot x -27$

Where x and y are measured in meters and centimeters, respectively.

The equation of the parabola that models the path of the long jumper through the air is $y = -x^{2}+12\cdot x -27.$

4 0

3 years ago