First, subtract y2 - y1 to find the vertical distance. Then, subtract x2 - x1 to find the horizontal distance.
Formula to find distance given two points.
Square root (X2 - X1)^2 + (Y2 - Y1)^2
Xa Ya Xb Yb
A = (3, -4) B = (-1, 3)
Xa goes into X2 and Xb goes into X1
(3 - (-1))^2
Ya goes into Y2 and Yb goes into Y1
(-4 - 3)^2
Square root (3 - (-1))^2 + (-4 - 3)^2
Square root (4)^2 + (-7)^2
Square root 16 + 49
Square root 65
= 8.06
The error was Drako had (3 - 4)^2 when it should have been (3 - (-4))^2 because a positive is subtracting a negative.
Answer:


Step-by-step explanation:
Given

--- lower diameter
--- upper diameter
Solving (a): The curved surface area
This is calculated as:

Where
--- lower radius
--- upper radius
And
---- l represents the slant height of the frustrum





So, we have:




Solving (b): The volume
This is calculated as:

This gives:





You just have to plug in each thing:
So f(0):
3(0)^2 - 4 = -4
so its not A
f(-2) and f(2):
3(-2)^2 - 4
3(2)^2 -4
now we don't even have to calculate these, anything to the power of an even number is a positive number so -2^2 and 2^2 both equal 4
B is correct, so you can do the others if you want to check, but if B is true the others shouldn't be true.
Hello,
y=2^(-x)
y=2^(2x)+3
==>2^(2x)+3=1/2^x
==>2^(3x)+3*2^x-1=0 (1)
Let's assume u=2^x
(1)==>u^3+3*u-1=0
which as 3 roots
u=0.322185354626 or
u = -0.161092677313 + i1.754380959784 or
u = -0.161092677313 - i1.754380959784.
Let's take the real solution
0.322185354626=2^x
==>x=ln(0.322185354626) / ln(2)
x=-1,6340371790199...
an other way is
f(x)=2^(3x)+3*2^x-1
f(-2)=1/64+3/4-1=-15/64 <0
f(-1)=1/8+1-1=1/8>0
==> there is a solution betheen -2<x<-1