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kirza4 [7]
3 years ago
9

You Try: Solve for x and y by using elimination. 4x + y = 7 4x - 2y = -2​

Mathematics
1 answer:
salantis [7]3 years ago
5 0

Answer:

\boxed {\boxed {\sf (1, 3) \ or \ x=1 \ and \  y=3}}}

Step-by-step explanation:

We are given this system of equations:

4x+y=7\\4x-2y=-2

We use elimination to solve to eliminate one of the variables, so we only have to work with one at a time. We do this by adding and subtracting the equations, and sometimes multiplying the entire equation by a number.

Notice how both equations have a 4x. This means they can easily be eliminated, without multiplying the equations by another number first. Let's subtract the 2 equations.

\ \ \ 4x+y=7\\ -(4x-2y)=-2

The 4x will cancel because 4x-4x=0.

\ \ \ \ y=7 \\ - (-2y) = -2

Since there are back to back negative signs, they become addition signs.

\ \ \ \ y=7 \\+2y=2

3y=9

We are solving for y , so we must isolate the variable. It is being multiplied by 3 and the inverse of multiplication is division. Divide both sides by 3.

3y/3=9/3\\y=3

Now we can substitute 3 in for y in the original equations. Let's use the first one.

4x+y=7\\4x+3=7

3 is being added to 4x. The inverse of addition is subtraction. Subtract 3 from both sides.

4x+3-3=7-3\\4x=4\\

x is being multiplied by 4. The inverse of multiplication is division. Divide both sides by 4.

4x/4=4/4\\x=1

x is equal to 1 and y is equal to 3. Coordinate points are written as (x, y). The solution to this system of equations is (1, 3).

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Answer:

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Step-by-step explanation:

<u>This is a right triangle as shown by the right angle.</u>

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So we have the opposite of A and the hypotenuse.

The trigonometric ratio that relates opposite side to hypotenuse is SINE.

sin\theta=\frac{opposite}{hypotenuse}

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<em>To solve for the angle, we use our calculator and find the inverse sin of \frac{1}{3} :</em>

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<em>Rounding to nearest tenth of a degree:</em>

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We are given the height h of a person from surface of sea level to be 350 m and we are to find the the distance to horizon d. Using the value in above expression we get:

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