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Shalnov [3]
3 years ago
7

A person who initially weighs 250 pounds loses 2 pounds per week. Let t represent the number of weeks and let W represent the pe

rson's weight, in pounds: W = − 2 t + 250
a. What is the person's weight after twelve weeks?
b. After how many weeks will the person weigh 234 pounds?
Mathematics
1 answer:
maksim [4K]3 years ago
8 0

Answer:

a. 226 pounds

b. 8 weeks

Step-by-step explanation:

To solve this problem, simply plug in the numbers for the variables it told you they correspond to. 12 is the number of weeks, and t represents the number of weeks, so we can plug 12 in for t.

W=-2(12)+250

Simplify and you'll have your answer.

W=-24+250\\W=226

For part B, 234 is the amount of pounds, and W represents the weight in pounds, so we can plug 234 in for W.

234=-2t+250\\-16=-2t\\8=t

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Graph the image of Kite BCDE after a translation 5 units down.​
NeTakaya

Answer:

See attachment for the translated kite

<em></em>

Step-by-step explanation:

Given

The attached image of BCDE

Required

Translate 5 units down

From the attachment;

B = (-7,0)

C = (0,5)

D =(-7,10)

E = (-10,5)

The rule to translate 5 units down is:

(x,y) \to (x,y-5)

So:

B' = (-7,-5)

C' = (0,0)

D' = (-7,5)

E' = (-10,0)

<em>See attachment for the translated kite</em>

3 0
3 years ago
PLS HELPPP !! BRAINLIEST!!
satela [25.4K]
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3 years ago
Solve 2x + 4 &gt; 16<br> A. X &lt; 6<br> B. X &gt; 6<br> C. X &lt; 10<br> D. X &gt; 10
Korvikt [17]

Answer:

B

2(6)+4 > 16             x > 6                 2(7) + 4 > 16

12+4=16                                            14+4>16       18>16

8 0
4 years ago
Determine whether the systems have one solution, no solution, or infinitely many solutions
Lerok [7]

Answer:

First system: no solution

Second system: one solution

Third system: one solution

Fourth system: infinite solutions

Fifth system: no solution

Step-by-step explanation:

First system: 3x-2y=3; 6x-4y=1

From the first equation: y = (3x - 3)/2

Using this value of y in the second equation:

6x - 6x + 6 = 1

6 = 1 -> System has no solution

Second system: 3x-5y=8; 5x-3y=2

From the first equation: x = (8 + 5y)/3

Using this value of x in the second equation:

5*(8 + 5y) - 9y = 6

40 + 25y - 9y = 6

16y = -34 -> y = -2.125

x = (8 - 5*2.125)/3 = -0.875

This system has one solution

Third system: 3x-2y=8; 4x-3y=1

 From the first equation: x = (8 + 2y)/3

Using this value of x in the second equation:

4*(8 + 2y) - 9y = 3

32 + 8y - 9y = 6

y = 26

x = (8 + 2*26)/3 = 20

This system has one solution

Fourth system: 3x-6y=3; 2x-4y=2

  From the first equation: x = 1 + 2y

Using this value of x in the second equation:

2*(1 + 2y) - 4y = 2

2 + 4y - 4y = 2

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This system has infinite solutions

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  From the first equation: x = (2 + 4y)/3

Using this value of x in the second equation:

2*(2 + 4y) - 8y = 1

4 + 8y - 8y = 2

4 = 2

This system has no solution

5 0
3 years ago
Andrew has 212 coins, all of
Igoryamba

Answer:

158 quarters

54 dimes

Step-by-step explanation:

Let d = no. of dimes

     q = no. of quarters

10d = value of all the dimes since each dime is worth 10 cents

and 25q = value of all the quarters since each quarter is worth 25 cents

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8 0
3 years ago
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