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choli [55]
3 years ago
8

What is the rule for the pattern 11,19,16,24,21,2926,...

Mathematics
2 answers:
ehidna [41]3 years ago
8 0
It is +8 -3, unless you have answer choices that says it a specific way?
Tema [17]3 years ago
7 0
Add 8, subtract 3, add 8, subtract three,etc.
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A certain city has a population of about 100,000. There are 3,101 people with red hair in the city. Which of these is closest to
Delicious77 [7]

Answer:

3%

hope this helps!

Step-by-step explanation:

8 0
3 years ago
Someone please help
VladimirAG [237]
The top answer is correct.
6 0
3 years ago
Complete the proofs using the most appropriate method. may require CPCTC.
n200080 [17]

For the first one, you did good. I will just suggest a couple things.

Statement              Reason

JK ≅ LM                   Given

<JKM ≅ < LMK        Given  (You did both of these steps so well done.)

MK ≅ MK              Reflexive Property (Your angle pair is congruent but isn't one of the interior angle of the triangles you are trying to prove.)

ΔJMK ≅ ΔLKM        SAS

Problem 2: (You also have a lot of great stuff here.)

Statement          Reason

DE ║ FG              Given

DE ≅ FG              Given

<DEF≅<FGH       Given

<EDF≅<GFH       Corresponding Angles (You don't need to know that F is the midpoint but you got corresponding angle pair which is correct.)

ΔEDF≅ΔGFH        ASA

<DFE≅<FHG       CPCTC  

3 0
3 years ago
Isabella save 2 nickels today, if she doubles the number of Nicole, she saves every day, how many days, including today, will it
Elden [556K]

Answer:

  8 days

Step-by-step explanation:

On day 8, Isabella will save 256 nickels, bringing her total to 510.

_____

The number of nickels saved on day n is 2^n. The total is 2^(n+1)-2.

_____

The above can be written down from your knowledge of binary sequences. If you want a more formal development, read on.

__

The number of nickels saved on day n is a geometric sequence with first term 2 and common ratio 2. The n-th term of the sequence is ...

  an = a1·r^(n-1) = 2·2^(n-1) = 2^n

The sum of n terms of the sequence is ...

  S = a1(r^n -1)/(r -1) = 2(2^n -1)/(2-1)

  S = 2^(n+1) -2

__

We want S > 500, so ...

  500 < 2^(n+1) -2

  502 < 2^(n+1)

  251 < 2^n

  log(251) < n·log(2)

  n > log(251)/log(2)

  n > 7.97 . . . . . . . . 8 days or more to save more than 500 nickels

3 0
4 years ago
What is the range for the set of data? 6, 7, 10, 12, 12, 13​
seropon [69]
The range of the data is 6-13
6 0
3 years ago
Read 2 more answers
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