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Dominik [7]
3 years ago
8

The common factors of 28 and 40

Mathematics
1 answer:
sveticcg [70]3 years ago
6 0
The factors of 28 are 1, 2, 4, 7, 14, and 28.
 
<span>The factors of 40 are 1, 2, 4, 5, 8, 10, 20, and 40.
 </span>
<span>The common factors are 1, 2, and 4.</span>
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Simplify.<br> (w^2 + 3w)-(w^2+5w-4<br><br> 8w-4<br> 2w^2 +8w-4<br> -2w+4<br> -2w
chubhunter [2.5K]

Answer:

-2w + 4

Step-by-step explanation:

Remove parenthesis because they make life semi-confusing but remember to distribute the negative: w^2 + 3w -w^2 - 5w + 4

Combine like terms: w^2 - w^2 cancel out ; 3w - 5w = -2w ; 4

-2w + 4

3 0
3 years ago
A beaker holds 50 ml of liquid. How many centiliters does the beaker hold.
Dvinal [7]
The beaker is holding 5 centiliters.
4 0
3 years ago
39% of 50 is what number
Simora [160]
Convert percent into a decimal by moving the percent sign two places to the left.

39% => 0.39

'Of' in math means multiply.

0.39 * 50 = 19.5
5 0
3 years ago
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Solve for x: 4/5 x + 4/3 =2x <br> X= ?
jeka57 [31]

Answer:

x = 10/9

Step-by-step explanation:

Solve for x:

(4 x)/5 + 4/3 = 2 x

Put each term in (4 x)/5 + 4/3 over the common denominator 15: (4 x)/5 + 4/3 = (12 x)/15 + 20/15:

(12 x)/15 + 20/15 = 2 x

(12 x)/15 + 20/15 = (12 x + 20)/15:

(12 x + 20)/15 = 2 x

Multiply both sides by 15:

(15 (12 x + 20))/15 = 15×2 x

(15 (12 x + 20))/15 = 15/15×(12 x + 20) = 12 x + 20:

12 x + 20 = 15×2 x

15×2 = 30:

12 x + 20 = 30 x

Subtract 30 x from both sides:

(12 x - 30 x) + 20 = 30 x - 30 x

12 x - 30 x = -18 x:

-18 x + 20 = 30 x - 30 x

30 x - 30 x = 0:

20 - 18 x = 0

Subtract 20 from both sides:

(20 - 20) - 18 x = -20

20 - 20 = 0:

-18 x = -20

Divide both sides of -18 x = -20 by -18:

(-18 x)/(-18) = (-20)/(-18)

(-18)/(-18) = 1:

x = (-20)/(-18)

The gcd of 20 and -18 is 2, so (-20)/(-18) = (-(2×10))/(2 (-9)) = 2/2×(-10)/(-9) = (-10)/(-9):

x = (-10)/(-9)

Multiply numerator and denominator of (-10)/(-9) by -1:

Answer: x = 10/9

3 0
3 years ago
a card is chosen at random from a deck of 52 cards it is then replaced and a second card is chosen what is the probability of ge
castortr0y [4]
There are 4 jacks and 4 eights so with replacement:

P(Jand8)=(1/13)^2=1/169
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