All categories

3 years ago

Select the correct answer.

Mathematics

1 answer:

stepladder [879]3 years ago

8 0

Answer:

y = 3x - 3, your answer is D.

Step-by-step explanation:

You might be interested in

1) On a city map drawn on a coordinate plane, the city park is located at (20, 4) and the school is at (20, 9). What is the dist

Marina CMI [18]

1) is 5 units which can be found by graphing
2) I got 240 by graphing this one as well

4 0

2 years ago

Read 2 more answers

How do I solve question 13 and 14?

xxMikexx [17]

Answer:

13. 13 or 17 (not sure about this, sorry)

14. 28

Step-by-step explanation:

13.

$a_{n} = \{a_{0}, a_{1}, a_{2}, a_{3}, a_{4}, ... \} \\$

if counting the sequence from $a_{0}$ then $a_{4}$ is 17, but if

$a_{n} = \{a_{1}, a_{2}, a_{3}, a_{4}, a_{5}, ... \} \\$

counting from $a_{1}$ , then $a_{4}$ is 13.

14.

$a_{10} = 1 + 3(10 - 1) = 1 + 3*9 = 28$

6 0

3 years ago

Use a half-angle identity to find the exact value

Tatiana [17]

Given:

$\cos 15^{\circ}$

To find:

The exact value of cos 15°.

Solution:

$$\cos 15^{\circ}=\cos\frac{ 30^{\circ}}{2}$

Using half-angle identity:

$$\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos (x)}{2}}$

$$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}$

Using the trigonometric identity: $\cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}$

$$=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}$

Let us first solve the fraction in the numerator.

$$=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}}$

Using fraction rule: $\frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}$

$$=\sqrt{\frac {2+\sqrt{3}}{4}}$

Apply radical rule: $\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$

$$=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}$

Using $\sqrt{4} =2$ :

$$=\frac{\sqrt{2+\sqrt{3}}}{2}$

$$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}$

5 0

3 years ago

PLEASE PLEASE HELP!!! Match each pair of matrices with its product matrix.

Butoxors [25]

Answer:

Step-by-step explanation:

Did the calculations myself, probably too late for these to be of any use but I'll leaave them here anyways for anyone else that needs it in the future. Love yall!

4 0

2 years ago

What set of transformations is performed on triangle ABC to form triangle A′B′C′?

Simora [160]

Answer: A translation 5 units down followed by a 180-degree counterclockwise rotation about the origin .

Step-by-step explanation:

From the given figure, the coordinates of ΔABC are A(-3,4), B(-3,1), C(-2,1) and the coordinates of ΔA'B'C' are A'(3,1), B'(3,4), C'(2,4).

When, a translation of 5 units down is applied to ΔABC, the coordinates of the image will be

Then applying 180° counterclockwise rotation about the origin, the coordinates of the image will be :-

which are the coordinates of ΔA'B'C'.

Hence, the set of transformations is performed on triangle ABC to form triangle A’B’C’ is " A translation 5 units down followed by a 180-degree counterclockwise rotation about the origin ".

4 0

3 years ago