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lesantik [10]
4 years ago
12

Which value is the 11th term in the sequence: -62, -54, -46, -38, -30, .......

Mathematics
1 answer:
klemol [59]4 years ago
8 0
A(11)= -62 + (11-1)8
-62 + 80
a(11)=18
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What is the distance between the points (5, 1) and (-3,-5)?
Klio2033 [76]

Answer:

10

Step-by-step explanation:

distance formula = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}

(x_1, y_1) = (5, 1)

(x_2, y_2) = (-3, -5)

\sqrt{ [(-3) - (5)]^2 + [(-5) - (1)]^2 }

\sqrt{ [-8]^2 + [-6]^2 }

\sqrt{ 64 + 36 }

\sqrt{ 100 }

= 10

6 0
3 years ago
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Find the values of x for which the series converges. (enter your answer using interval notation.) ∞ (x + 9)n n = 1 find the sum
Naddika [18.5K]
If the series is

\displaystyle\sum_{n=1}^\infty(x+9)^n


then it is geometric, which we know converges as long as the base is smaller than 1 in absolute value, i.e. |x+9|. "Expanding" the absolute value, this is equivalent to

-1

When x is in this interval, the geometric sum converges to

\displaystyle\sum_{n=1}^\infty(x+9)^n=\frac1{1-(x+9)}=-\frac1{x+8}
7 0
4 years ago
Reduce 438form 1514. The result is _____.
Alexeev081 [22]

Answer:

-1076

Step-by-step explanation:

3 0
3 years ago
B) The angle of depression from an observation tower to boat A is 28 degrees. The angle of depression from the same point of the
xz_007 [3.2K]

Answer:

53 meters

Step-by-step explanation:

The angle between a viewer's horizontal line of sight and the line of sight down towards a particle is called the angle of depression. For example if a viewer is sitting at the top of a tower and looking down on a car, the angle between the viewer's horizontal line of sight and the line of sight to which he looks at the car is the angle of depression.

A sketch of the positions of the boats and the tower has been attached to this response.

As shown,

the distance between the two boats A and B is marked x meters.

the horizontal distance between boat A and the foot of the tower is y meters.

the horizontal distance between boat A and the foot of the tower is  x + y meters.

the height of the tower is 60 meters.

the angle of depression of boat A is 28°

the angle of depression of boat B is 45°

To find the value of y, from triangle DBC we use the trigonometric ratio for tangent. i.e

tan 45° = \frac{60}{y}

1 = \frac{60}{y}

y = 60 meters

To find the value of x, from triangle ABC we use the trigonometric ratio for tangent. i.e

tan 28° = \frac{60}{x+y}

<em>Where y = 60 meters</em>

tan 28° = \frac{60}{x+60}

0.5317 = \frac{60}{x+60}

x + 60 = \frac{60}{0.5317}

x + 60 = 112.85

x = 112.85 - 60

x = 52.85 meters

Therefore, boat A is about 53 meters from boat B

3 0
3 years ago
Find the product mentally.
jonny [76]
(2j+7)(2j−7)

=(2j+7)(2j+−7)

=(2j)(2j)+(2j)(−7)+(7)(2j)+(7)(−7)

=4j2−14j+14j−49

=4j2−49

5 0
4 years ago
Read 2 more answers
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