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eduard
3 years ago
13

Please.....................

Mathematics
1 answer:
Wewaii [24]3 years ago
8 0

Answer:

B

Step-by-step explanation:

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Which of the following equations matches the function shown above?
yanalaym [24]

Answer:

C=y=sin1/2x

Step-by-step explanation:

As given in the graph:

Amplitude= 1

period=2π

Finding function of sin that have period of 4π and amplitude 1

A: y=1/2sinx

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1/2

b=1

c=0

d=0

Amplitude=|a|

                =1/2

Period= 2π/b

         =2π

B: y=sin2x

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1

b=2

c=0

d=0

Amplitude=|a|

                =1

Period= 2π/2

         =π

C: y=sin1/2x

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1

b=1/2

c=0

d=0

Amplitude=|a|

                =1

Period= 2π/1/2

         =4π

D: y=sin1/4x

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1

b=1/4

c=0

d=0

Amplitude=|a|

                =1

Period= 2π/1/4

         =8π

Hence only c: y=sin1/2x has period of 2π and amplitude 1

5 0
3 years ago
HELP ASAP!!!!!
OlgaM077 [116]
It will take 5 months and the payments will be as follows:

Month 1: $375 to Mini and $3.15 to Murk
Month 2: $375 to Mini and $3.15 to Murk
Month 3: $165.58 to Mini and $209.42 to Murk
Month 4: $375 to Murk
Month 5: $87.36 to Murk 
4 0
3 years ago
Read 2 more answers
How do I solve this
IgorLugansk [536]

Answer:

divide

Step-by-step explanation:


7 0
3 years ago
How do i solve 426 to the nearest ten
Dmitry [639]
Youll need to provide more information
4 0
3 years ago
Read 2 more answers
The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 330 grams and a standard deviati
just olya [345]

Answer:

Weights of at least 340.1 are in the highest 20%.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 330, \sigma = 12

a. Highest 20 percent

At least X

100-20 = 80

So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.

Z = \frac{X - \mu}{\sigma}

0.842 = \frac{X - 330}{12}

X - 330 = 12*0.842

X = 340.1

Weights of at least 340.1 are in the highest 20%.

3 0
3 years ago
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