Let the cost of 3 bags of chocolate be x and that of gummy be y. Thus to solve the question we form systems of equation as:
3x+7y=22...............i
x+3y=8.....ii
from ii
x=8-3y........iii
substituting iii in i we get:
3(8-3y)+7y=22
24-9y+7y=22
-2y=-2
y=1
thus the value of x=8-3*1=5
thus the price of each bag of chocolate is $5 and that of gummy is $1
Answer:
m= 6.83, m= 41/6
Step-by-step explanation:
Answer:
Reduction is centered at (2,2)
Scale factor = 1/3
Hope this helps!
Mf+3n all over 5 is the answer to find Q
