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leva [86]
3 years ago
13

you buy seven bags of gummy bears and 3 bag of chocolate and your total is $22 your friend buys a your friend buys three bags of

gummy bears in it and one bag of the chocolate and her total is $8 what is the price of a bag of Gummy Bears and a bag of chocolate
Mathematics
1 answer:
tino4ka555 [31]3 years ago
8 0
Let the cost of 3 bags of chocolate be x and that of gummy be y. Thus to solve the question we form systems of equation as:
3x+7y=22...............i
x+3y=8.....ii
from ii
x=8-3y........iii
substituting iii in i we get:
3(8-3y)+7y=22
24-9y+7y=22
-2y=-2
y=1
thus the value of x=8-3*1=5
thus the price of each bag of chocolate is $5 and that of gummy is $1
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3 years ago
2+2+4+32<br> please solve :D
Arturiano [62]

Answer:

40

Step-by-step explanation:

2+2 = 4

4+4 = 8

8+32= 40

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3 years ago
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Benjamin has to wear a uniform to school. His uniform is made up of tan or blue pants and a blue or white collared shirt. Benjam
oee [108]

Explanation:

As his uniform is made up of tan or blue pants and a blue or white collared shirt.

So, there are possibly four combinations which are as follows:

  • tan pants/blue shirt
  • tan pants/white shirt
  • blue pants/blue shirt
  • blue pants/white shirt

As Benjamin carries an extra piece of white shirt. So, he has a little bit better than 25% chance of wearing his favorite combination.

So,

  • Probability of getting tan pants = 2/4 = 1/2
  • Probability of getting white shirt = 3/5

The probability of getting both can be computed by simply multiplying 2/4 and 3/5.

So,

  • Probability of getting both = 1/2 × 3/5 = 3/10 ⇒ 30%

<em>Keywords: probability, chance</em>

<em> Learn more about from /brainly.com/question/14382310</em>

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3 years ago
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6 0
3 years ago
Four boys weighed themselves in different pairs and alone. The weights of the pairs were 110 kg, 112 kg, 113 kg, 118 kg, 121 kg,
brilliants [131]

The lost pair of weight can be found by subtracting the a known pair from

the total weight leaving the value of the lost pair.

<u>The lost weight of a pair of boys is 120 kg</u>

Reasons:

Let <em>a</em>, <em>b</em>, <em>c</em>, and <em>d</em><em> </em>represent the weights of the four boys, we have;

The number of ways of selecting pairs (two boys) of boys from a group of

four is given using combination formula as follows;

_nC_r = \dfrac{n!}{r! \cdot (n - r)!}

Which gives;

_4C_2 = \dfrac{4!}{2! \cdot (4 - 2)!} = 6

₄C₂ = 6

Therefore, the weights of the pairs are;

a + b = 110

a + c = 112

a + d = 113

b + c = 118

b + d = 121

c + d = Lost weight

  • c + d = Lost weight

a + b + c + d = 230 (given)

Therefore;

The lost weight, c + d = 230 - (a + b)

Which gives;

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The lost weight = c + d = 120

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