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3 years ago

Please help i dont understand at all :(

Mathematics

1 answer:

andrey2020 [161]3 years ago

3 0

180 - 46 - 24 = 110

d+ 80 = 110
d = 30

answer
d = 30

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Joseph borrowed a book from a library. The library charged a fixed rental for the book and a late fee for every day the book was

Paha777 [63]

The coefficient, 0.25, of the expression represents the late fee for every day the book was overdue.

And the constant, 2, represents the fixed rental fee.

The variable, x, represents the number of days Joseph had the book for.

Hope this helps :)

5 0

3 years ago

The Jacksons and the Simpsons were competing in the final leg of the Amazing Race, which was 240240240 kilometers long. In their

meriva

Answer:

240/(v+40) + 1 > 240/v

Step-by-step explanation:

Both parties traveled a distance of 240 km.

Simpsons took off at average speed of 40 km/h & 1 hour later: 240/(v+40) + 1

Jacksons took off at average speed of v km/h: 240/v

6 0

3 years ago

Suzy is shopping at a book sale.The table show prices for paperback books.

Salsk061 [2.6K]

Answer:

6,9

Step-by-step explanation:

Got it right on edg

3 0

2 years ago

What times what equals 8,000

alexira [117]

4,000 × 2 = 8,000 hope thats what you meant!

4 0

2 years ago

Read 2 more answers

The following are the weights,in pounds, of some dogs at a kennel: 36,45,29,39,51,49.

VashaNatasha [74]

Answer:

Median = 42 pounds

Step-by-step explanation:

It is given that the following are the weights,in pounds, of some dogs at a kennel: 36,45,29,39,51,49.

Arrange the data in ascending order.

29, 36, 39, 45, 49, 51

Total number of terms = 6 (even)

So, the formula for median is

$Median=\dfrac{\frac{n}{2}\text{th term}+(\frac{n}{2}+1)\text{th term}}{2}$

$Median=\dfrac{\frac{6}{2}\text{th term}+(\frac{6}{2}+1)\text{th term}}{2}$

$Median=\dfrac{3\text{rd term}+4\text{th term}}{2}$

$Median=\dfrac{39+45}{2}$

$Median=42$

Hence, the median weight is 42 pounds.

To find the median, units of the data should be same. If one of the weights were given in kilograms, then we cannot find median.

4 0

3 years ago