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dolphi86 [110]
3 years ago
12

Helpppppppppppppppppppplp

Mathematics
1 answer:
DENIUS [597]3 years ago
7 0

Help in what ? I cant see the photo

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What is the solution to the system of equations? 3x + 10y = -47 5x- 7y = 40<br>Please and thank u
anastassius [24]

Answer:

x=1, y=-5

Step-by-step explanation:

Given equations are:

3x+10y=-47\ Eqn\ 1\\and\\5x-7y=40\ Eqn\ 2

In order to solve the equation

Multiplying Eqn 1 by 5 and eqn 2 by 3 and subtracting them

So,

Eqn 1 becomes

15x+50y=-235

Eqn 2 becomes

15x-21y=120

Subtracting 2 from a

15x+50y - (15x-21y) = -235-120

15x+50y-15x + 21y = -355

71y = -355

y = -355/71

y =-5

Putting y= -5 in eqn 1

3x+10(-5) = -47

3x -50 = -47

3x = -47+50

3x = 3

x = 3/3

x = 1

Hence the solution is:

x=1, y=-5

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3 years ago
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The answer is (x+3)(x+7)
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Geometry help what is it will give brainliest
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For this problem, we can say that corresponding angles are congruent, or the same, this also means that their angle measures have to be the same. Then, our equations for our angles will be vertical angles, which means that they must equal each other. So we would then write our equation as 3x+20=4x+10 or 4x+10=3x+20. Then, to combine like terms, we will subtract 3x from both sides, resulting in x+10=20. Then we will subtract 10 from both sides, resulting in x=10.
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