1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Paladinen [302]
3 years ago
13

What is the value expression to 3 1/4 - 1 7/8 =show how?

Mathematics
1 answer:
Andrei [34K]3 years ago
3 0
3 1/4 - 1 7/8
First, subtract the whole numbers (3 - 1 = 2):           
= 2 1/4 - 7/8
Convert 1/4 to 2/8:
= 2 2/8 - 7/8
Borrow 1=8/8 from the 2:
= 1 10/8 - 7/8
Subtract 7/8 from 10/8:
= 1 3/8

The answer is 1 3/8

Alternatively, use improper fractions:
3 1/4 = 13/4 = 26/8
1 7/8 = 15/8
26/8 - 15/8 = 11/8 = 1 3/8
You might be interested in
Can someone help me please
Sveta_85 [38]
The second expression uses the greatest common factor and the distributive property to rewrite the sum 60 + 24.
60, 24
60 = 2² × 3 × 5
24 = 2³ × 3
We take the highest common factors - 
=> 2² × 3
=> 4 × 3
=> GCF: 12
Therefore, the correct factored expression would be 12(5 + 2), which matches the second expression. Hope this helped!
8 0
4 years ago
Read 2 more answers
Consider this composite figure. 2 cones. The top cone has a height of 5 centimeters and radius of 3 centimeters. The bottom cone
posledela

Answer:

39

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
Let C(x) be the statement "x has a cat," let D(x) be the statement "x has a dog," and let F(x) be the statement "x has a ferret.
jek_recluse [69]

Answer:

\mathbf{a)} \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\\\mathbf{b)} \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee \; F(x)\\\mathbf{c)} \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)\\\mathbf{d)} \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)\\\mathbf{e)} \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

Step-by-step explanation:

Let X be a set of all students in your class. The set X is the domain. Denote

                                        C(x) -  ' \text{$x $ has a cat}'\\D(x) -  ' \text{$x$ has a dog}'\\F(x) -  ' \text{$x$ has a ferret}'

\mathbf{a)}

Consider the statement '<em>A student in your class has a cat, a dog, and a ferret</em>'. This means that \exists x \in X so that all three statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                         \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)

\mathbf{b)}

Consider the statement '<em>All students in your class have a cat, a dog, or a ferret.' </em>This means that \forall x \in X at least one of the statements C(x), D(x) and F(x) is true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                        \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee F(x)

\mathbf{c)}

Consider the statement '<em>Some student in your class has a cat and a ferret, but not a dog.' </em>This means that \exists x \in X so that the statements C(x), F(x) are true and the negation of the statement D(x) . We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                      \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)

\mathbf{d)}

Consider the statement '<em>No student in your class has a cat, a dog, and a ferret..' </em>This means that \forall x \in X none of  the statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as a negation of the statement in the part a), as follows

\neg \left( \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\right) \iff \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)

\mathbf{e)}

Consider the statement '<em> For each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.' </em>

This means that for each of the statements C, F and D there is an element from the domain X so that each statement holds true.

We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

           \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

5 0
4 years ago
Please someone actually help :((( honestly im just gonna drop out
Lorico [155]

Answer:

12

Step-by-step explanation:

4u - 8u = -63 + 15 ( collecting like terms)

-4u = -48

u = 12

8 0
3 years ago
Read 2 more answers
An interior designer purchased 4 1/2 yard
KiRa [710]
Well, is just a matter of addition, namely 4  1/2 + 6  2/3 + 9  1/4.

now, let's change all mixed fractions firstly, to "improper" fractions, and proceed from there,

\bf \stackrel{mixed}{4\frac{1}{2}}\implies \cfrac{4\cdot 2+}{1}\implies \stackrel{improper}{\cfrac{9}{2}}&#10;\\\\\\&#10;\stackrel{mixed}{6\frac{2}{3}}\implies \cfrac{6\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{20}{3}}&#10;\\\\\\&#10;\stackrel{mixed}{9\frac{1}{4}}\implies \cfrac{9\cdot 4+1}{}\implies \stackrel{improper}{\cfrac{37}{4}}\\\\&#10;-------------------------------\\\\

\bf \cfrac{9}{2}+\cfrac{20}{3}+\cfrac{37}{4}\impliedby \textit{our LCD is clearly \underline{12}}\implies \cfrac{(6)9+(4)20+(3)37}{12}&#10;\\\\\\&#10;\cfrac{245}{12}\implies 20\frac{5}{12}
7 0
4 years ago
Other questions:
  • Look at the graph below: First line joins ordered pairs negative 4, 3 and 2, negative 3. Second line joins negative 4, negative
    5·1 answer
  • When 6 less than 3 times a number is increased by 2, it's at least 5 times the same number decreased by 8.
    11·1 answer
  • Write an integer that represents this scenario:<br><br> 18-point gain
    11·2 answers
  • Twice the difference of a number and 4 is at least 29
    11·1 answer
  • The distance between the points (5, -2) and (-7, 3) is
    9·1 answer
  • Simplify <br>-1^3 <br>(-5)^2 ​
    12·1 answer
  • Is there an association being a boy and wanting a $10 ticket? Explain.
    5·1 answer
  • What are the next three terms in the sequence 1, 7, 13, 19, ... ?
    6·1 answer
  • Nancy is knitting a scarf. It takes her 0.2 of an hour to knit each inch of the scarf. She wants the length of the scarf to be 6
    10·2 answers
  • Solve the following <br> -5x + 3 = 2x - 1
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!