The Jacobian has determinant
5y-3x+2=0 to y=mx+b form
1 answer:
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The Jacobian has determinant
Answer:
y = x + 1
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = - 3x + 1 ← is in slope- intercept form
with slope m = - 3
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
=
, thus
y = x + c ← is the partial equation of the perpendicular line
To find c substitute (6, 3) into the partial equation
3 = 2 + c ⇒ c = 3 - 2 = 1
y = x + 1 ← equation of perpendicular line