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3 years ago

7w−(2+w)=2(3w−1)

Mathematics

2 answers:

Xelga [282]3 years ago

5 0

The correct answer is C

Llana [10]3 years ago

4 0

Simplify brackets

(7w - 2 - w = 2(3w - 1)

simplify 7w - 2 - w to 6w - 2

(6w - 2 = 2(3w - 1)

Expand

(6w - 2 = 6w - 2)

Since both sides are equal, there are infinitely many solutions

Answer: C) INFINITELY MANY

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63% of US adults opposed to taxes on junk food and soda. You randomly select 10 US adults. Find the probability that the number

WARRIOR [948]

Answer:

a) 0.0008 = 0.08% probability that the number of adults who oppose special tax on junk food and soda is exactly one.

b) 0.9644 = 96.44% probability that the number of adults who oppose special tax on junk food and soda is at least four.

c) 0.7795 = 77.95% probability that the number of adults who oppose special tax on junk food and soda is less than eight.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they are opposed to taxes on junk food and soda, or they are not. Each adult is independent of other adults, which means that the binomial probability distribution is used to solve the question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

63% of US adults opposed to taxes on junk food and soda.

This means that $p = 0.63$

You randomly select 10 US adults.

This means that $n = 10$

(a) exactly one

This is $P(X = 1)$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{10,1}.(0.63)^{1}.(0.37)^{9} = 0.0008$

0.0008 = 0.08% probability that the number of adults who oppose special tax on junk food and soda is exactly one.

(b) at least four

This is

$P(X \geq 4) = 1 - P(X < 4)$

In which

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.63)^{0}.(0.37)^{10} \approx 0$

$P(X = 1) = C_{10,1}.(0.63)^{1}.(0.37)^{9} = 0.0008$

$P(X = 2) = C_{10,2}.(0.63)^{2}.(0.37)^{8} = 0.0063$

$P(X = 3) = C_{10,3}.(0.63)^{3}.(0.37)^{7} = 0.0285$

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.0008 + 0.0063 + 0.0285 = 0.0356$

$P(X \geq 4) = 1 - P(X < 4) = 1 - 0.0356 = 0.9644$

0.9644 = 96.44% probability that the number of adults who oppose special tax on junk food and soda is at least four.

(c) less than eight

This is

$P(X < 8) = 1 - P(X \geq 8)$

In which

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{10,8}.(0.63)^{8}.(0.37)^{2} = 0.1529$

$P(X = 9) = C_{10,1}.(0.63)^{9}.(0.37)^{1} = 0.0578$

$P(X = 10) = C_{10,2}.(0.63)^{10}.(0.37)^{0} = 0.0098$

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1529 + 0.0578 + 0.0098 = 0.2205$

$P(X < 8) = 1 - P(X \geq 8) = 1 - 0.2205 = 0.7795$

0.7795 = 77.95% probability that the number of adults who oppose special tax on junk food and soda is less than eight.

5 0

3 years ago

Factor completely. 10x^3 + 2x^2 + 5x + 1

jonny [76]

Answer:

(5x + 1)x(2x^2+1)

Step-by-step explanation:

6 0

3 years ago

Just answer for the points

Alenkasestr [34]

Answer:

Answer:

Step-by-step explanation:

Thanks for free points!

6 0

3 years ago

4. What are the coefficients in the polynomial 7x² - 4x + 6? (1 poin

skad [1K]

Answer:

D.) 7 and -4

Step-by-step explanation:

Coefficients are numbers placed directly before a variable.

(7) is a coefficient because it is placed before x².

(-4) is a coefficient because it is placed before x. The negative is included.

(6) is not a coefficient because it is not altering any variable through multiplication/division.

5 0

2 years ago

Students who attend Washington Middle School are either in seventh or eighth grade. At the end of the first semester 25% of the

Irina18 [472]

Answer:

There are 1240 students who attended Washington Middle School.

Step-by-step explanation:

Given:

Students who attend Washington Middle School are either in seventh or eighth grade.

At the end of the first semester 25% of the students at Washington Middle School were on the honor roll.

Seventh graders represented 60% of the students on the honor roll.

If 124 students on the honor roll were in eighth grade.

Now, to find the students attend Washington Middle School.

Let the total number of students be $x.$

So, the students at Washington Middle School were on the honor roll:

25% of $x$

$=\frac{25}{100} \times x$

$=\frac{25x}{100}$

$=\frac{x}{4}$

As, given seventh graders represented 60% of the students.

So, the students on the honor roll represented as seventh graders:

$60\%\ of\ \frac{x}{4}$

$=\frac{60}{100} \times \frac{x}{4}$

$=0.6\times \frac{x}{4}$

$=\frac{0.6x}{4}$

As, 124 students on the honor roll were in eighth graders.

Thus,

According to question:

$\frac{x}{4} -\frac{0.6x}{4} =124$

$\frac{x-0.6x}{4} =124$

$\frac{0.4x}{4} =124$

Multiplying both sides by 4 we get:

$0.4x=496$

Dividing both sides by 0.4 we get:

$x=1240.$

Therefore, there are 1240 students who attended Washington Middle School.

6 0

4 years ago