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Diano4ka-milaya [45]
3 years ago
6

Help me pleaseeeeeeeeee

Mathematics
1 answer:
Marizza181 [45]3 years ago
3 0
The answer is False!!!
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Perform the indicated operation 10ab/c^3d ÷ 15ab^3/7c^3d^4​
andrew11 [14]

Step-by-step explanation:

=  \frac{10ab}{ {c}^{3}d }  \div  \frac{15a {b}^{3} }{7 {c}^{3}  {d}^{4} }

=  \frac{10ab}{ {c}^{3} d}  \times  \frac{7 {c}^{3} {d}^{4}  }{15a {b}^{3} }

=  \frac{70ab {c}^{3} {d}^{4}  }{15a {b}^{3}  {c}^{3} d}

=  \frac{70}{15}  {a}^{1 - 1}  {b}^{1 - 3}  {c}^{3 - 3}  {d}^{4 - 1}

=  \frac{14}{3}  {a}^{0}  {b}^{ - 2}  {c}^{0}  {d}^{3}

=  \frac{14 {d}^{3} }{3 {b}^{2} }

6 0
2 years ago
Which shape could be thought of as being created by stacking congruent polygons
seraphim [82]
Rectangular, prism and square

6 0
3 years ago
Read 2 more answers
I️ have to use 15 as Y
statuscvo [17]
-1/5of 15 =-3 then add 3 2/5th which is 17/2 so -3+17/2 = 11/2=5 1/2
7 0
3 years ago
Find the distance between the 2 points (6, - 4) and (2, - 7). Please show me how you found it.
Serga [27]
\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ 6}}\quad ,&{{ -4}})\quad 
%  (c,d)
&({{ 2}}\quad ,&{{ -7}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
d=\sqrt{[2-6]^2+[-7-(-4)]^2}\implies d=\sqrt{(2-6)^2+(-7+4)^2}
5 0
3 years ago
Four points are labeled on the number line. M K L zo 0.5 1 Which point best represents 3? F. Point K G. H. Point 2 Point M Point
viva [34]

The point that best represents 1/3 is point M .

The number line ranges from 0 to 0.5 with 10 divi

8 0
1 year ago
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