Answer:
Since the area of the rectangle is 6 square centimeters, you just think of multiples of 6. These multiples will give possible lengths for the rectangle. Possible multiples include: 1&6 2&3 Then you just find the perimeter of the rectangle with your possible side lengths So let's start with: 1&6 So two of the side lengths are 1 And the other two side lengths are 6 So you would just find the sum of the four side lengths to find the perimeter 1 + 1 + 6 + 6 = 14 Now let's try 2&3 Two of the side lengths are 2 The other two side lengths are 3 Now to find the perimeter just add up the four side lengths 2 + 2 + 3 + 3 =10 Now compare the two perimeters Which is bigger? 14? Or 10? Since fourteen is bigger than the greatest possible perimeter for the rectangle is 14cm
Step-by-step explanation:
ADDINDGTHE NUMBERS UP
It Should be 15/x for what I see in my notes
Surface area = 2(6*3) + 2(6*2) + 2*(2*3) = 36+24+12 = 72 cm^2
Answer:
x = 13
y = 18.38
Step-by-step explanation:
tan 45 = x/13 (tangent = opposite / adjacent)
1 = x/13
multiply both sides by 13
x = 13
cos 45 = 13/y (cosine = adjacent / hypotenuse
0.7071 = 13/y
multiply both side by y
0.7071y = 13
divide both side by 0.7071
y = 18.38
