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anzhelika [568]
3 years ago
7

Exponential form of log(4)5

Mathematics
1 answer:
Aloiza [94]3 years ago
7 0

Answer:

you need to multiply 4 by 5

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Simplify: x^5. X-^5?
WARRIOR [948]

Answer:

i believe the answer you are looking for is 1?

Step-by-step explanation:

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3 years ago
What is the percentage of 48g of fat out of a 70g allowance
Elenna [48]
<span>48/70=0.6857
</span><span>0.6857x100=68.57%</span>
5 0
3 years ago
(sin teta + sec teta)^ + (cos teta+ cosec teta )^ = (1 + sec x cosec)^
ArbitrLikvidat [17]
(sin\theta+sec\theta)^2+(cos\theta+cosec\theta)^2=(1+sec\theta\ cosec\theta)^2\\\\L=sin^2\theta+2sin\theta\cdot\frac{1}{cos\thewta}+\frac{1}{cos^2\theta}+cos^2\theta+2cos\theta\cdot\frac{1}{sin\theta}+\frac{1}{sin^2\theta}\\\\=(sin^2\theta+cos^2\theta)+\frac{2sin\theta}{cos\theta}+\frac{2cos\theta}{sin\theta}+\frac{1}{cos^2\theta}+\frac{1}{sin^2\theta}

=1+\frac{2sin^2\theta+2cos^2\theta}{sin\theta\ cos\theta}+\frac{sin^2\theta+cos^2\theta}{sin^2\theta\ cos^2\theta}\\\\=1+\frac{2(sin^2\theta+cos^2\theta)}{sin\theta\ cos\theta}+\frac{1}{sin^2\theta\ cos^2\theta}\\\\=1+\frac{2}{sin\theta\ cos\theta}+\frac{1}{sin^2\theta\ cos^2\theta}\\\\=1^2+2sec\theta\ cosec\theta+sec^2\theta\ cosec^2\theta\\\\=(1+sec\theta\ cosec\theta)^2=R
4 0
3 years ago
Find a statement that is equivalent to the absolute value equation |9x−9|=7.
Olegator [25]

Answer:9x-9=7 or 9x-9=-7

Step-by-step explanation:

An absolute value is the distance from zero, therefore the answer can not be negative. In this case, 9x-9=7 and 9x-9=-7 both work, because 7 and -7 are the same distance from zero.

8 0
3 years ago
The number 9.37 rounded to the nearest tenth is 9.4 Is this correct?y or y not
PSYCHO15rus [73]
Yes, this is correct. The tenths place is the first number to the right of the decimal. There is a 3 in that spot
To find if it rounds up or down, follow this rule.
Less than 5 round down and greater than 5 round up.
For this you look to the number next to it which is 7.
It rounds up so it is 9.4
8 0
3 years ago
Read 2 more answers
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