Answer:
Use your calculator to find the value of:

Write all the figures on your calculator's display for th
Answer:
3.5
Step-by-step explanation:
Answer: Each bow needs 4.67 yards of ribbon.
Step-by-step explanation:
We know that each roll has 20 yd.
She used 3 + 1/2 rolls, then the total length used will be (3 + 1/2) times the length of each roll, this is:
(3 + 1/2)*20 yd = (6/2 + 1/2)*20yd = (7/2)*20yd = 70 yd.
With tose 70 yards of ribbon, she made 15 bows, then the length of ribbon used in each bow will be equal to the quotient between the total length used and the number of ribbons made with it, this is:
70yd/15 = 4.67 yards
Each bow needs 4.67 yards of ribbon.
C=480
solve
480=24n+35
minus 35 both sides
445=24n
divide both sides by 24
18.541666666666666666666666666667=n
<span>so about 18 cakes</span>
The sample space (list of outcomes) is:
DFNR; DFRN; DRFN; DRNF; DNFR; DNRF;
NFDR; NFRD; NRFD; NRDF; NDRF; NDFR;
RFDN; RFND; RNFD; RNDF; RDFN; RDNF;
FRDN; FRND; FNRD; FNDR; FDRN; FDNR
P(Dave beside Natalie) = 1/2
P(B,G,B,G or G,B,G,B) = 1/3
P(boys in the middle) = 1/6
P(Frida beside Natalie) = 1/2
P(Robbie between Frida & Natalie) = 1/6
P(Natalie between Dave & Robbie) = 1/6
Explanation
Letting D=Dave, R=Robbie, N=Natalie, and F=Frida you get the list of possibilites above.
For P(Dave beside Natalie), look for DN or ND. This appears 12 times out of the 24 possibilities above; 12/24 = 1/2.
For P(B,G,B,G or G,B,G,B), we have the possibilities DFRN, DNRF, RFDN, RNDF, FRND, FDNR, NDFR, NRFD. There are 8 possibilites out of 24; 8/24 = 1/3.
For P(Frida beside Natalie), look for NF or FN. This appears 12 times out of the 24 possibilities; 12/24 = 1/2.
For Robbie between Frida and Natalie, look for FRN or NRF. This appears 4 times out of 24; 4/24 = 1/6.
For Natalie between Robbie and Dave, look for RND or DNR. This appears 4 times out of 24; 4/24 = 1/6.
