Andrew walked for 3/4 miles after his break
<h3>
How to calculate the number of miles Andrew walked after the break ? </h3>
Andrew went for a walk
The trail he took is 1 1/4 miles long
He walked for 1/2 miles before stopping for a water break
After the break, he continued the journey
He continued the journey without stopping
The distance Andrew walked after his break can be calculated as follows
5/4 - 1/2
= 5-2/4
= 3/4
Hence Andrew walked for 3/4 miles after taking the break
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B) 29
Because 20^2+21^2=c^2
7978 years
Step-by-step explanation:
A = A02^(-t/hl)
where hl = half-life.
Dividing both sides by A0 and taking the logarithm, we get
ln(A/A0) = -(t/hl)ln2
or solving for t,
t= -(hl)ln(A/A0)/ln2
note that A/A0 = 0.38
t = -(5715 yrs)[ln(0.38)/ln2]
= 7978 years
Answer:
A ) y=-1/2x+2
Step-by-step explanation:
since the equation is y=2x+4 and the points are (-2,3) and the line is perpendicular to that equation
y=-1/2x+b
enter the point (-2,3)
3=1+b
b=2
so
y=-1/2x+2
Answer:
Step-by-step explanation:
From the figure attached,
If the figures shown are congruent (Equal in shape and size), length of all the sides must be equal.
Therefore, sides sides CD and GH must be equal in measures.
Distance between the two points 
and 
is given by,
d = 
Length of the side CD having ends C(-4, 4) and D(0, 5) will be,
CD = 
CD = 
= 
Length of GH having ends G(0, -4) and H(4, -5) will be,
GH = 
= 
=
Therefore, m(CD) = m(GH)
Similarly, we can prove all corresponding sides of two figures equal in measure.
This shows ABCD ≅ EFGH.
